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If 'a' and 'b' are positive integers such that a2 – b2 = 19, then the value of 'a' is : (SSC MTS 2017)
- a)20
- b)19
- c)10
- d)9
Correct answer is option 'C'. Can you explain this answer?
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If a and b are positive integers such that a2 – b2 = 19, then th...
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If a and b are positive integers such that a2 – b2 = 19, then th...
According to question,
a2 – b2 = 19
(a + b) (a – b) = 19
Since 19 is prime, one of (a + b) (a – b) is 19
Therefore, (10)2 – (9)2 = 19
∴ a = 10
a2 – b2 = 19
(a + b) (a – b) = 19
Since 19 is prime, one of (a + b) (a – b) is 19
Therefore, (10)2 – (9)2 = 19
∴ a = 10
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If a and b are positive integers such that a2 – b2 = 19, then the value of a is : (SSC MTS 2017)a)20b)19c)10d)9Correct answer is option 'C'. Can you explain this answer?
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