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If (r cosθ - √3)2 + (r sinθ – 1)2 = 0, then the value of  is equal to   (SSC CHSL 2014)
  • a)
    4/5
  • b)
    5/4
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If (r cosθ - √3)2 + (r sinθ – 1)2 = 0, then th...
(r cosθ - √3)2 + (r sinθ – 1)2 = 0
On comparing, we get
(r cos θ – 3 )2 = 0 ⇒ r cos θ = 3 ... (i)
and (r sin θ – 1)2 = 1 ⇒ r sin θ = 1 ... (ii)
On dividing (ii) from (i), we get
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If (r cosθ - √3)2 + (r sinθ – 1)2 = 0, then the value ofis equal to (SSC CHSL 2014)a)4/5b)5/4c)d)Correct answer is option 'A'. Can you explain this answer?
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