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Directions: Select a single answer choice.
Q. If j and k are even integers and j < k,="" which="" of="" the="" following="" equals="" the="" number="" of="" even="" integers="" that="" are="" greater="" than="" j="" and="" less="" than="" />
  • a)
    k − j − 2 / 2
  • b)
    k − j − 1 / 2
  • c)
    k − j / 2
  • d)
    k − j
  • e)
    k − j − 1
Correct answer is option 'A'. Can you explain this answer?
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Directions: Select a single answer choice.Q. If j and k are even inte...
Since j and k are even integers, it follows that k = j + 2n for some integer n. Consider the sequence of even integers from j to k.
j, j + (2)(1), j + (2)(2), j + (2)(3), . . . , j + (2)(n − 1), j + 2n
Note that there are n − 1 integers in the sequence between j and k, and these are the even integers greater than j and less than k. Therefore the answer is n − 1, but the answer must be given in terms of j and k. Since k = j + 2n, you have n = k - j/2 and so
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Directions: Select a single answer choice.Q. If j and k are even integers and j a)k − j − 2 / 2b)k − j − 1 / 2c)k − j / 2d)k − je)k − j − 1Correct answer is option 'A'. Can you explain this answer?
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