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A particle start motion with initial velocity 45m/s along x axis from origin acceleration of partical is -10 m/s distance travelled in 5th sec is?
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A particle start motion with initial velocity 45m/s along x axis from ...
Given:
Initial velocity (u) = 45 m/s
Acceleration (a) = -10 m/s²
Time (t) = 5 s

Using the equations of motion:

1. Velocity (v) at any time (t) can be calculated using the equation:
v = u + at

Substituting the given values:
v = 45 m/s + (-10 m/s²) * 5 s
v = 45 m/s - 50 m/s
v = -5 m/s

2. Displacement (s) at any time (t) can be calculated using the equation:
s = ut + (1/2)at²

Substituting the given values:
s = 45 m/s * 5 s + (1/2) * (-10 m/s²) * (5 s)²
s = 225 m - 125 m
s = 100 m

Answer:
The particle travels a distance of 100 meters in the 5th second.
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A particle start motion with initial velocity 45m/s along x axis from origin acceleration of partical is -10 m/s distance travelled in 5th sec is?
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