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The distance between two negatively charged dust particle is 1mm and they repel each other with a force of 4×10^'-5 N. if the charge on one particle is 4 times that of the other then find out the number of electrons charging them separately.?
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The distance between two negatively charged dust particle is 1mm and t...
Given data:
- Distance between the two negatively charged dust particles: 1mm
- Repulsive force between the particles: 4×10^-5 N
- Charge on one particle is 4 times that of the other

Calculating the charge on each particle:
1. Let the charges on the two particles be q and 4q.
2. According to Coulomb's law, the force of repulsion between the particles is given by:
F = k * (q1 * q2) / r^2
where F is the repulsive force, k is the Coulomb's constant, q1 and q2 are the charges on the particles, and r is the distance between them.
3. Substituting the given values, we get:
4×10^-5 = k * (q * 4q) / (1 * 10^-3)^2
4×10^-5 = k * 4q^2 / 10^-6
q^2 = 10^-5 / (4k)
q = sqrt(10^-5 / (4k))

Calculating the number of electrons:
1. The charge on an electron is approximately 1.6 x 10^-19 C.
2. To find the number of electrons, we need to divide the charge on each particle by the charge on one electron.
3. Let's assume q = n * e, where n is the number of electrons and e is the charge on one electron.
4. Therefore, n = q / e = sqrt(10^-5 / (4k)) / (1.6 x 10^-19)
By following the above calculations, you can determine the number of electrons charging the particles separately.
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