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When a current carrying circular loop is placed in a magnetic field its net force is zero . This is because 2 equal and opposite forces act on it the magnitude of each force = I×B×L= I×B×2πr. The magnitude of torque = F×2r=I×B×2π×2r= 4×π r^2I×B= 4× A×I×B . But the original formula does not include 4. Am I Wrong somewhere?
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When a current carrying circular loop is placed in a magnetic field it...
Explanation of the Formula for Torque on a Current-Carrying Circular Loop in a Magnetic Field

The Formula
The formula for the torque on a current-carrying circular loop in a magnetic field is given by:

τ = IABsinθ

where τ is the torque, I is the current, A is the area of the loop, B is the magnetic field strength, and θ is the angle between the magnetic field and the plane of the loop.

The Two Forces
When a current-carrying circular loop is placed in a magnetic field, two equal and opposite forces act on it. The magnitude of each force is given by:

F = IBL

where F is the force, I is the current, B is the magnetic field strength, and L is the length of the loop.

The Net Force
Since the two forces are equal and opposite, they cancel out each other and the net force on the loop is zero.

The Magnitude of Torque
The magnitude of the torque on the loop is given by:

τ = F x 2r

where r is the radius of the loop.

The 4 Factor
The original formula does not include the factor of 4. However, it is important to note that the formula assumes that the loop is a rectangle with sides of length L and 2r. In reality, the loop is a circle with a diameter of 2r. Therefore, the actual area of the loop is πr^2, which is four times smaller than the area assumed in the formula.

So, the correct formula for the torque on a current-carrying circular loop in a magnetic field is:

τ = 4IArB

where A is the area of the loop, which is equal to πr^2.
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Read the following text and answer the following questions on the basis of the same:Super magnet The term super magnet is a broad term and encompasses several families of rare-earth magnets that include seventeen elements in the periodic table; namely scandium, yttrium, and the fifteen lanthanides. These elements can be magnetized, but have Curie temperatures below room temperature. This means that in their pure form, their magnetism only appears at low temperatures. However, when they form compounds with transition metals such as iron, nickel, cobalt, etc. Curie temperature rises well above room temperature and they can be used effectively at higher temperatures as well. The main advantage they have over conventional magnets is that their greater strength allows for smaller, lighter magnets to be used. Super magnets are of two categories:(i) Neodymium magnet: These are made from an alloy of neodymium, iron, and boron. This material is currently the strongest known type of permanent magnet. It is typically used in the construction of head actuators in computer hard drives and has many electronic applications, such as electric motors, appliances, and magnetic resonance imaging (MRI).(ii) Samarium-cobalt magnet: These are made from an alloy of samarium and cobalt. This second strongest type of rare Earth magnet is also used in electronic motors, turbo-machinery, and because of its high temperature range tolerance may also have many applications for space travel, such as cryogenics and heat resistant machinery. Rare-earth magnets are extremely brittle and also vulnerable to corrosion, so they are usually plated or coated to protect them from breaking, chipping, or crumbling into powder. Since super magnets are about 10 times stronger than ordinary magnets, safe distance should be maintained otherwise these may damage mechanical watch, CRT monitor, pacemaker, credit cards, magnetically stored media etc. These types of magnets are hazardous for health also. The greater force exerted by rare-earth magnets creates hazards that are not seen with other types of magnet. Magnets larger than a few centimeters are strong enough to cause injuries to body parts pinched between two magnets or a magnet and a metal surface, even causing broken bones. Neodymium permanent magnets lose their magnetism 5% every 100 years. So, in the truest sense Neodymium magnets may be considered as a permanent magnet.Neodymium and Samarium are

Read the following text and answer the following questions on the basis of the same: Super magnet The term super magnet is a broad term and encompasses several families of rare-earth magnets that include seventeen elements in the periodic table; namely scandium, yttrium, and the fifteen lanthanides. These elements can be magnetized, but have Curie temperatures below room temperature. This means that in their pure form, their magnetism only appears at low temperatures. However, when they form compounds with transition metals such as iron, nickel, cobalt, etc. Curie temperature rises well above room temperature and they can be used effectively at higher temperatures as well. The main advantage they have over conventional magnets is that their greater strength allows for smaller, lighter magnets to be used. Super magnets are of two categories: (i) Neodymium magnet: These are made from an alloy of neodymium, iron, and boron. This material is currently the strongest known type of permanent magnet. It is typically used in the construction of head actuators in computer hard drives and has many electronic applications, such as electric motors, appliances, and magnetic resonance imaging (MRI). (ii) Samarium-cobalt magnet: These are made from an alloy of samarium and cobalt. This second strongest type of rare Earth magnet is also used in electronic motors, turbo-machinery, and because of its high temperature range tolerance may also have many applications for space travel, such as cryogenics and heat resistant machinery. Rare-earth magnets are extremely brittle and also vulnerable to corrosion, so they are usually plated or coated to protect them from breaking, chipping, or crumbling into powder. Since super magnets are about 10 times stronger than ordinary magnets, safe distance should be maintained otherwise these may damage mechanical watch, CRT monitor, pacemaker, credit cards, magnetically stored media etc. These types of magnets are hazardous for health also. The greater force exerted by rare-earth magnets creates hazards that are not seen with other types of magnet. Magnets larger than a few centimeters are strong enough to cause injuries to body parts pinched between two magnets or a magnet and a metal surface, even causing broken bones. Neodymium permanent magnets lose their magnetism 5% every 100 years. So, in the truest sense Neodymium magnets may be considered as a permanent magnet.Neodymium permanent magnets lose their magnetism ____ % every 100 years.

When a current carrying circular loop is placed in a magnetic field its net force is zero . This is because 2 equal and opposite forces act on it the magnitude of each force = I×B×L= I×B×2πr. The magnitude of torque = F×2r=I×B×2π×2r= 4×π r^2I×B= 4× A×I×B . But the original formula does not include 4. Am I Wrong somewhere?
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When a current carrying circular loop is placed in a magnetic field its net force is zero . This is because 2 equal and opposite forces act on it the magnitude of each force = I×B×L= I×B×2πr. The magnitude of torque = F×2r=I×B×2π×2r= 4×π r^2I×B= 4× A×I×B . But the original formula does not include 4. Am I Wrong somewhere? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about When a current carrying circular loop is placed in a magnetic field its net force is zero . This is because 2 equal and opposite forces act on it the magnitude of each force = I×B×L= I×B×2πr. The magnitude of torque = F×2r=I×B×2π×2r= 4×π r^2I×B= 4× A×I×B . But the original formula does not include 4. Am I Wrong somewhere? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a current carrying circular loop is placed in a magnetic field its net force is zero . This is because 2 equal and opposite forces act on it the magnitude of each force = I×B×L= I×B×2πr. The magnitude of torque = F×2r=I×B×2π×2r= 4×π r^2I×B= 4× A×I×B . But the original formula does not include 4. Am I Wrong somewhere?.
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