The velocity of a body moving in a straight line is increased by apply...
Suppose a body of mass (m) and is under an acceleration due to which is initial speed u at time (T) BCom final position velocity (v ) at time (t)the force on the body is F=mav^2 = u^2+2as=) mv^2 - 1/2 mu^2 = ( ma)s=) Fs = 1/2 mv^2 - 1/2mv^2 wOrk done = final K.E - initial K.Efirst the work done by the force to increase the speed of moving body will be stored in its as it increasing kinetic energy hope it'll be help U frndcheer"""
The velocity of a body moving in a straight line is increased by apply...
Explanation:
When a force is applied to an object, work is done on the object, which is the product of the force and the distance moved in the direction of the force. This work is converted into kinetic energy, which is the energy possessed by a moving object due to its motion.
Proof:
Let the initial velocity of the body be "u" and the final velocity be "v". The change in velocity is given by:
Δv = v - u
The force "F" is applied for a distance "d" in the direction of motion. The work done by the force is given by:
W = Fd
Using Newton's second law of motion, we can express the force in terms of mass and acceleration:
F = ma
where "m" is the mass of the body and "a" is the acceleration produced by the force. Using the equations of motion, we can express the final velocity in terms of the initial velocity, acceleration and distance moved:
v² = u² + 2ad
Substituting for "a" in terms of "F" and "m", we get:
a = F/m
Substituting for "a" and "v" in the equation for work done, we get:
W = Fd = mad = (mv² - mu²)/2
The increase in kinetic energy is given by:
ΔK.E. = (1/2)mv² - (1/2)mu²
Substituting for "W" in terms of "m", "v" and "u", we get:
ΔK.E. = W
Therefore, the increase in kinetic energy of the body is equal to the work done by the force on the body.
To make sure you are not studying endlessly, EduRev has designed Class 9 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 9.