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A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static fuction between the block and the surface is 0.6. if the acceleration of the truck is 5 m/sec2 , what is the frictional force acting on the block ?
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A block of mass 1 kg lies on a horizontal surface in a truck. The coef...
Understanding the Situation
A block of mass 1 kg is placed on a horizontal surface inside a truck that accelerates at 5 m/s². The coefficient of static friction between the block and the surface is 0.6.
Calculating the Forces
- Weight of the Block: The weight (W) of the block is calculated using the formula:
Weight = mass × gravity
Here, gravity is approximately 9.81 m/s², so:
Weight = 1 kg × 9.81 m/s² = 9.81 N
- Normal Force (N): The normal force acting on the block is equal to its weight in this case, since there are no vertical movements. Therefore:
N = 9.81 N
Frictional Force Calculation
- Maximum Static Friction (F_max): The maximum static friction can be calculated using the formula:
F_max = coefficient of static friction × normal force
F_max = 0.6 × 9.81 N = 5.886 N
- Required Frictional Force (F): To keep the block from slipping, the frictional force must match the force needed to accelerate the block with the truck. This force is given by:
F = mass × acceleration
F = 1 kg × 5 m/s² = 5 N
Conclusion
- Since the required frictional force (5 N) is less than the maximum static friction (5.886 N), the block will not slip.
- Therefore, the frictional force acting on the block is 5 N, which is sufficient to prevent slipping as the truck accelerates.
A block of mass 1 kg is placed on a horizontal surface inside a truck that accelerates at 5 m/s². The coefficient of static friction between the block and the surface is 0.6.
Calculating the Forces
- Weight of the Block: The weight (W) of the block is calculated using the formula:
Weight = mass × gravity
Here, gravity is approximately 9.81 m/s², so:
Weight = 1 kg × 9.81 m/s² = 9.81 N
- Normal Force (N): The normal force acting on the block is equal to its weight in this case, since there are no vertical movements. Therefore:
N = 9.81 N
Frictional Force Calculation
- Maximum Static Friction (F_max): The maximum static friction can be calculated using the formula:
F_max = coefficient of static friction × normal force
F_max = 0.6 × 9.81 N = 5.886 N
- Required Frictional Force (F): To keep the block from slipping, the frictional force must match the force needed to accelerate the block with the truck. This force is given by:
F = mass × acceleration
F = 1 kg × 5 m/s² = 5 N
Conclusion
- Since the required frictional force (5 N) is less than the maximum static friction (5.886 N), the block will not slip.
- Therefore, the frictional force acting on the block is 5 N, which is sufficient to prevent slipping as the truck accelerates.
Community Answer
A block of mass 1 kg lies on a horizontal surface in a truck. The coef...
6 N
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A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static fuction between the block and the surface is 0.6. if the acceleration of the truck is 5 m/sec2 , what is the frictional force acting on the block ?
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A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static fuction between the block and the surface is 0.6. if the acceleration of the truck is 5 m/sec2 , what is the frictional force acting on the block ? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static fuction between the block and the surface is 0.6. if the acceleration of the truck is 5 m/sec2 , what is the frictional force acting on the block ? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static fuction between the block and the surface is 0.6. if the acceleration of the truck is 5 m/sec2 , what is the frictional force acting on the block ?.
A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static fuction between the block and the surface is 0.6. if the acceleration of the truck is 5 m/sec2 , what is the frictional force acting on the block ? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static fuction between the block and the surface is 0.6. if the acceleration of the truck is 5 m/sec2 , what is the frictional force acting on the block ? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static fuction between the block and the surface is 0.6. if the acceleration of the truck is 5 m/sec2 , what is the frictional force acting on the block ?.
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