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Please help the correct sequence of quantum numbers (n,l,m) resp of the electron of outermost orbit of chromium atom is?a) 3,2,1,0b)4,0,0,1/2c)4,2,1,1/2d)3,0,0,-1/2
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Please help the correct sequence of quantum numbers (n,l,m) resp of th...
The correct sequence of quantum numbers (n,l,m) for the electron of the outermost orbit of a chromium atom is:

b) 4,0,0,1/2

Explanation:

1. Quantum Numbers:
Quantum numbers are the values that describe the properties and behavior of electrons in an atom. There are four quantum numbers: principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m), and spin quantum number (s).

2. Principal Quantum Number (n):
The principal quantum number (n) describes the energy level or shell in which an electron resides. It determines the size and energy of the electron's orbital. The values of n can be any positive integer starting from 1.

3. Azimuthal Quantum Number (l):
The azimuthal quantum number (l) describes the shape of the electron's orbital. It defines the subshell within a given energy level. The values of l can range from 0 to (n-1) for a given value of n.

4. Magnetic Quantum Number (m):
The magnetic quantum number (m) describes the orientation of the orbital in space. It specifies the exact orbital within a subshell. The values of m range from -l to +l, including zero.

5. Spin Quantum Number (s):
The spin quantum number (s) describes the spin state of an electron. It can have two possible values: +1/2 (spin-up) or -1/2 (spin-down).

6. Chromium Atom:
The electron configuration of a chromium atom is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵. Chromium has an atomic number of 24, which means it has 24 electrons. The outermost electron of chromium is located in the 4s orbital.

7. Determining the Quantum Numbers:
To determine the quantum numbers of the electron in the outermost orbit of chromium, we look at the electron configuration.

- The principal quantum number (n) for the outermost electron in the 4s orbital is 4.
- The azimuthal quantum number (l) for an s orbital is 0.
- The magnetic quantum number (m) for an s orbital is 0.
- The spin quantum number (s) can be either +1/2 or -1/2.

8. Correct Sequence:
Based on the above analysis, the correct sequence of quantum numbers for the electron of the outermost orbit of a chromium atom is:

4, 0, 0, 1/2 (option b)

This means that the outermost electron in the chromium atom has a principal quantum number of 4, an azimuthal quantum number of 0 (s orbital), a magnetic quantum number of 0, and a spin quantum number of +1/2.
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Please help the correct sequence of quantum numbers (n,l,m) resp of th...
B
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Please help the correct sequence of quantum numbers (n,l,m) resp of the electron of outermost orbit of chromium atom is?a) 3,2,1,0b)4,0,0,1/2c)4,2,1,1/2d)3,0,0,-1/2
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Please help the correct sequence of quantum numbers (n,l,m) resp of the electron of outermost orbit of chromium atom is?a) 3,2,1,0b)4,0,0,1/2c)4,2,1,1/2d)3,0,0,-1/2 for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Please help the correct sequence of quantum numbers (n,l,m) resp of the electron of outermost orbit of chromium atom is?a) 3,2,1,0b)4,0,0,1/2c)4,2,1,1/2d)3,0,0,-1/2 covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Please help the correct sequence of quantum numbers (n,l,m) resp of the electron of outermost orbit of chromium atom is?a) 3,2,1,0b)4,0,0,1/2c)4,2,1,1/2d)3,0,0,-1/2.
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