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What is the correct increasing order of reactivity of the following compounds towards electrophilic aromatic substitution reaction?

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Increasing Order of Reactivity towards Electrophilic Aromatic Substitution Reaction

Electrophilic aromatic substitution (EAS) reactions involve the substitution of an electrophile into an aromatic ring. The reactivity of different compounds towards EAS reactions depends on various factors such as the presence of electron-donating or electron-withdrawing groups, resonance effects, and steric hindrance. To determine the correct increasing order of reactivity towards EAS reactions for the given compounds, we need to analyze these factors.

Compound A: Benzene

Benzene is a highly reactive compound towards EAS reactions. It has a delocalized pi electron system, which provides stability to the aromatic ring. The high electron density in the benzene ring makes it highly susceptible to electrophilic attack.

Compound B: Toluene

Toluene is a derivative of benzene with a methyl group (-CH3) attached to the ring. The methyl group is electron-donating, which increases the electron density on the ring. This electron-donating effect makes toluene more reactive than benzene towards EAS reactions.

Compound C: Nitrobenzene

Nitrobenzene contains a nitro group (-NO2) attached to the benzene ring. The nitro group is strongly electron-withdrawing due to the presence of the electronegative nitrogen and oxygen atoms. This electron-withdrawing effect decreases the electron density on the ring, making nitrobenzene less reactive than benzene and toluene towards EAS reactions.

Compound D: Anisole

Anisole is a methoxybenzene derivative with a methoxy group (-OCH3) attached to the ring. The methoxy group is electron-donating, similar to the methyl group in toluene. Therefore, anisole is more reactive than nitrobenzene but less reactive than benzene and toluene towards EAS reactions.

Based on the above analysis, the correct increasing order of reactivity towards EAS reactions for the given compounds is:

Nitrobenzene < anisole="" />< toluene="" />< />

This order is determined by the electron-donating or electron-withdrawing nature of the substituents attached to the benzene ring. Electron-donating groups increase the electron density on the ring, making the compound more reactive towards EAS reactions. Conversely, electron-withdrawing groups decrease the electron density on the ring, reducing the reactivity towards EAS reactions.
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Can you explain the answer of this question below:On the basis of aromaticity, there are three types of compounds i.e. aromatic, non-aromatic and antiaromatic.The increasing order of stability of these compounds are is under:Anti-aromatic compound non-aromatic compound aromatic compounds. Compounds to be aromaticfollow the following conditions (according to valence bond theory)(i) The compounds must be be cyclic in structure having (4n + 2) e, where n = Hckels number = 0, 1,2, 3 et.c(ii) The each atoms of the cyclic structure must have unhybridised p-orbital i.e. the atoms of thecompounds have unhybridised p-orbital i.e. usually have sp2 hybrid or planar.(iii) There must be a ring current of electrons in the ring or cyclic structure i.e. cyclic structure mustundergo resonance .Compounds to be anti-aromatic, it must have 4ne where n = 1, 2 and it must be planar and undergoresonance. Non-aromatic compounds the name itself spells that compounds must be non-planarirrespective of number of electrons. Either it has 4ne or (4n + 2) electrons it does not matter.The rate of reaction of any aromatic compounds depends upon the following factors:(i) Electron density(ii) stability of carbocation producedHigher the amount of electron density of the ring, higher will be its rate towards aromatic electrophilicsubstitution and vice-versa. Similarly, higher will be the stability of the produced carbocation after theattack of electrophile, higher will be its rate towards aromatic electrophilic substitution. There is a greateffect of kinetic labelling on the rate of aromatic electrophilic substitution. As we known that higher theatomic weight or, molecualr weight, higher will be the van der Waals force of attraction or, bond energy.Since there will be effect of kienetic labelling if the 2nd step of the reaction will be the slow step, (r.d.s.)otherwise there will be no effect of kinetic labelling.Q. Which of the following is correct order of the rate of reaction of C6H6, C6D6 and C6T6 towardsnitrations?A:C6H6 C6D6 C6T6B:C6H6 = C6D6 = C6T6C:C6H6 C6D6 = C6T6D:C6T6 C6D6 C6H6The answer is b.

On the basis of aromaticity, there are three types of compounds i.e. aromatic, non-aromatic and antiaromatic. The increasing order of stability of these compounds are is under: Anti-aromatic compound < non-aromatic compound < aromatic compounds. Compounds to be aromaticfollow the following conditions (according to valence bond theory)(i) The compounds must be be cyclic in structure having (4n + 2)π e–, where n = Hückel’s number = 0, 1, 2, 3 et.c(ii) The each atoms of the cyclic structure must have unhybridised p-orbital i.e. the atoms of the compounds have unhybridised p-orbital i.e. usually have sp2 hybrid or planar.(iii) There must be a ring current of π electrons in the ring or cyclic structure i.e. cyclic structure mustundergo resonance .Compounds to be anti-aromatic, it must have 4nπe– where n = 1, 2… and it must be planar and undergo resonance. Non-aromatic compounds the name itself spells that compounds must be non-planarirrespective of number of π electrons. Either it has 4nπe– or (4n + 2) π electrons it does not matter.The rate of reaction of any aromatic compounds depends upon the following factors:(i) Electron density(ii) stability of carbocation producedHigher the amount of electron density of the ring, higher will be its rate towards aromatic electrophilic substitution and vice-versa. Similarly, higher will be the stability of the produced carbocation after the attack of electrophile, higher will be its rate towards aromatic electrophilic substitution. There is a great effect of kinetic labelling on the rate of aromatic electrophilic substitution. As we known that higher the atomic weight or, molecualr weight, higher will be the van der Waal’s force of attraction or, bond energy. Since there will be effect of kienetic labelling if the 2nd step of the reaction will be the slow step, (r.d.s.) otherwise there will be no effect of kinetic labelling.Q. Which of the following is correct order of the rate of reaction of C6H6, C6D6 and C6T6 towardssulphonation?

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