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Let a and b be the roots of the quadratic equation x^2 sqrt6x 3=0.then a^23 b^23 a^14 b^14/a^15 b^15 a^10 b^10?
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Let a and b be the roots of the quadratic equation x^2 sqrt6x 3=0.then...
Quadratic Equation


To find the value of expression involving the roots of a quadratic equation, we first need to find the roots of the given quadratic equation. Let's consider the quadratic equation given:

x^2 sqrt6x 3 = 0

Finding the Roots


We can solve the given quadratic equation by factoring, completing the square, or using the quadratic formula. However, the given equation seems to be incomplete, as there is no coefficient of x^2 term. Therefore, let's assume the coefficient of x^2 term is 1:

x^2 + sqrt(6)x + 3 = 0

Now, we can proceed to find the roots of the quadratic equation. By factoring, completing the square, or using the quadratic formula, we get:

x = (-sqrt(6) ± sqrt(6 - 4(1)(3))) / (2(1))
= (-sqrt(6) ± sqrt(-12)) / 2
= (-sqrt(6) ± 2i√(3)) / 2
= -sqrt(6)/2 ± i√(3)

Therefore, the roots of the quadratic equation are:

a = -sqrt(6)/2 + i√(3)
b = -sqrt(6)/2 - i√(3)

Expression Involving Roots


Now, let's evaluate the given expression:

a^23 b^23 a^14 b^14 / a^15 b^15 a^10 b^10

We can simplify this expression by canceling out common factors:

a^23 b^23 a^14 b^14 / a^15 b^15 a^10 b^10
= (a^(23+14) b^(23+14)) / (a^(15+10) b^(15+10))
= (a^37 b^37) / (a^25 b^25)
= a^(37-25) b^(37-25)
= a^12 b^12

Therefore, the simplified expression is a^12 b^12.

In conclusion, the given quadratic equation has roots a = -sqrt(6)/2 + i√(3) and b = -sqrt(6)/2 - i√(3). The expression involving these roots simplifies to a^12 b^12.
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Let a and b be the roots of the quadratic equation x^2 sqrt6x 3=0.then a^23 b^23 a^14 b^14/a^15 b^15 a^10 b^10?
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Let a and b be the roots of the quadratic equation x^2 sqrt6x 3=0.then a^23 b^23 a^14 b^14/a^15 b^15 a^10 b^10? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let a and b be the roots of the quadratic equation x^2 sqrt6x 3=0.then a^23 b^23 a^14 b^14/a^15 b^15 a^10 b^10? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let a and b be the roots of the quadratic equation x^2 sqrt6x 3=0.then a^23 b^23 a^14 b^14/a^15 b^15 a^10 b^10?.
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