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Let a, b = R be such that the function f given by t(x) = tnbx )+tr^ 2 - ax, x=0 has extreme values at?
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Let a, b = R be such that the function f given by t(x) = tnbx )+tr^ 2 ...
Extreme Values of Function f

In this problem, we are given a function f(x) defined as t(x) = tnbx * tr^2 - ax, where a and b are real numbers. We need to determine the conditions under which the function has extreme values.


Definition of Extreme Values

An extreme value of a function occurs at a point where the derivative of the function is either zero or does not exist. These points are called critical points. To find extreme values, we need to find the critical points of the function.


Finding the Derivative of f(x)

To find the derivative of the function f(x), we can use the product rule. Let's denote t(x) as u(x) and tr^2 - ax as v(x). Applying the product rule, we have:

f'(x) = u'(x)v(x) + u(x)v'(x)


Finding the Critical Points

To find the critical points, we need to solve the equation f'(x) = 0. Let's set f'(x) = 0 and solve for x:

0 = u'(x)v(x) + u(x)v'(x)

0 = (tnbx)' * (tr^2 - ax) + tnbx * (tr^2 - ax)'

0 = (tnb)' * (tr^2 - ax) + tnb * (tr^2 - ax)'

0 = nb * (tr^2 - ax) + tnbx * (-a)

0 = nb * tr^2 - nb * ax - tnbx * a

0 = nb * tr^2 - tnbx * a - nb * ax

0 = nb * tr^2 - a * tnbx - nb * ax

0 = nb * tr^2 - ax * (tnb + nb)

ax * (tnb + nb) = nb * tr^2

ax = (nb * tr^2) / (tnb + nb)


Conditions for Extreme Values

The function f(x) has extreme values at the points where the derivative f'(x) is either zero or does not exist. From the equation we obtained for the critical points, we can see that the function will have extreme values when:


  • tnb + nb ≠ 0 (to avoid division by zero)

  • a ≠ 0 (to avoid a constant function)


Therefore, the conditions for extreme values of the function f(x) are:

tnb + nb ≠ 0 and a ≠ 0

These conditions ensure that the derivative f'(x) exists and is not zero, allowing us to find the critical points and determine the extreme values of the function.
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Let a, b = R be such that the function f given by t(x) = tnbx )+tr^ 2 - ax, x=0 has extreme values at?
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Let a, b = R be such that the function f given by t(x) = tnbx )+tr^ 2 - ax, x=0 has extreme values at? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let a, b = R be such that the function f given by t(x) = tnbx )+tr^ 2 - ax, x=0 has extreme values at? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let a, b = R be such that the function f given by t(x) = tnbx )+tr^ 2 - ax, x=0 has extreme values at?.
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