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The magnetic field inside a current carrying toroidal solenoid is B, if its radius is doubled and the current through it is also doubled keeping the total number of turns same, the magnetic field inside the solenoid will be:
  • a)
    B/2
  • b)
    B
  • c)
    2B
  • d)
    4B
Correct answer is option 'B'. Can you explain this answer?
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Explanation:

Effect of Doubling Radius:
- When the radius of the toroidal solenoid is doubled, the magnetic field inside is inversely proportional to the radius.
- Therefore, the magnetic field inside the solenoid will become B/2.

Effect of Doubling Current:
- When the current passing through the solenoid is doubled, the magnetic field inside is directly proportional to the current.
- Therefore, the magnetic field inside the solenoid will become 2B.

Overall Effect:
- When both the radius and current are doubled, the net effect on the magnetic field inside the solenoid is the combination of the individual effects.
- The magnetic field inside the solenoid will be B/2 (due to doubling radius) * 2 (due to doubling current) = B.
Therefore, the correct answer is option 'B' which states that the magnetic field inside the solenoid will remain the same when the radius and current are both doubled, keeping the total number of turns the same.
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The magnetic field inside a current carrying toroidal solenoid is B, if its radius is doubled and the current through it is also doubled keeping the total number of turns same, the magnetic field inside the solenoid will be:a)B/2b)Bc)2Bd)4BCorrect answer is option 'B'. Can you explain this answer?
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