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A body of mass 0.1kg is executing SHM according to the equation x=o.o5 cos(100t + 3pie/4)meters. Find the following
1. The frequency of oscillation?
2. Initial phase?
3. Maximum velocity?
4. Total energy?
Most Upvoted Answer
A body of mass 0.1kg is executing SHM according to the equation x=o.o5...
It is like x=Acos(wt+$)...Here A is amplitude;w is angulr frqncy;$ is phase angle...1)f=w/2pie=50/pie...2)$=3pie/4..3)vmax=Aw=0.05×100=5..4)total enrgy=1/2mA^2w^2=1/2×0.1×10^4×25×10^-4=1.25J ....HOPE U GOT IT
Community Answer
A body of mass 0.1kg is executing SHM according to the equation x=o.o5...
The given equation for the simple harmonic motion (SHM) is x = 0.05 cos(100t - 3π/4) meters. We need to find the frequency of oscillation, initial phase, maximum velocity, and total energy.

1. Frequency of Oscillation:
The equation for the displacement of a particle executing SHM is given by x = A cos(ωt + φ), where A is the amplitude, ω is the angular frequency, t is time, and φ is the phase angle.

Comparing the given equation with the general equation, we can see that the angular frequency ω = 100 rad/s. The frequency of oscillation (f) is related to the angular frequency by the equation f = ω/(2π).

Therefore, the frequency of oscillation is f = 100/(2π) ≈ 15.92 Hz.

2. Initial Phase:
The initial phase (φ) is the phase angle when t = 0. From the given equation, we can see that the phase angle is -3π/4.

Therefore, the initial phase is φ = -3π/4 radians.

3. Maximum Velocity:
The velocity of a particle executing SHM is given by v = -Aω sin(ωt + φ).

To find the maximum velocity, we need to find the maximum value of the absolute value of v. The maximum value of the absolute value of sin function is 1.

Therefore, the maximum velocity is vmax = Aω = 0.05 * 100 = 5 m/s.

4. Total Energy:
The total energy (E) of a particle executing SHM is the sum of its kinetic energy (K) and potential energy (U). The equation for total energy is E = K + U.

The kinetic energy of the particle is given by K = (1/2)mv^2, where m is the mass of the body and v is the velocity.

The potential energy of the particle is given by U = (1/2)kx^2, where k is the spring constant and x is the displacement.

In this case, there is no mention of the spring constant or any information about the force acting on the body. Therefore, we cannot calculate the spring constant or the potential energy. Hence, we cannot calculate the total energy.

To summarize:
1. The frequency of oscillation is approximately 15.92 Hz.
2. The initial phase is -3π/4 radians.
3. The maximum velocity is 5 m/s.
4. The total energy cannot be calculated without information about the spring constant or potential energy.
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A body of mass 0.1kg is executing SHM according to the equation x=o.o5 cos(100t + 3pie/4)meters. Find the following 1. The frequency of oscillation?2. Initial phase?3. Maximum velocity?4. Total energy?
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A body of mass 0.1kg is executing SHM according to the equation x=o.o5 cos(100t + 3pie/4)meters. Find the following 1. The frequency of oscillation?2. Initial phase?3. Maximum velocity?4. Total energy? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A body of mass 0.1kg is executing SHM according to the equation x=o.o5 cos(100t + 3pie/4)meters. Find the following 1. The frequency of oscillation?2. Initial phase?3. Maximum velocity?4. Total energy? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 0.1kg is executing SHM according to the equation x=o.o5 cos(100t + 3pie/4)meters. Find the following 1. The frequency of oscillation?2. Initial phase?3. Maximum velocity?4. Total energy?.
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