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One mole of an ideal gas expands at a constant temperature of 300 K from an initial volumeof 10 litres to a final volume of 20 litres. The work done (in J) in expanding the gas is(R = 8.31 J/mole-K) (log 2 = 0.3010)Correct answer is '1728'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One mole of an ideal gas expands at a constant temperature of 300 K from an initial volumeof 10 litres to a final volume of 20 litres. The work done (in J) in expanding the gas is(R = 8.31 J/mole-K) (log 2 = 0.3010)Correct answer is '1728'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One mole of an ideal gas expands at a constant temperature of 300 K from an initial volumeof 10 litres to a final volume of 20 litres. The work done (in J) in expanding the gas is(R = 8.31 J/mole-K) (log 2 = 0.3010)Correct answer is '1728'. Can you explain this answer?.

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