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A particle performing SHM has time period 2π/√3 and path length 4cm the displacement from mean position at which acceleration is equal to velocity is?
Most Upvoted Answer
A particle performing SHM has time period 2π/√3 and path length 4cm th...
I am damn sure it's 1 cm..path length =4cmamplitude=path length /2=2cm NOW,magnitude of velocity and acceleration we know that is [omega√(A²-y²)] and (omega)²ysince acceleration=velocity hence on equating we get omega=√(A²-y²)/ywe r to find y ...nd omega = 2π/given time period =√3finally u'll get y=1 ....
Community Answer
A particle performing SHM has time period 2π/√3 and path length 4cm th...
Yeah..felicita is absolutely correct ...
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A particle performing SHM has time period 2π/√3 and path length 4cm the displacement from mean position at which acceleration is equal to velocity is?
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