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The radii of curvature of two faces of a biconvex lens are 0.2 m and 0.25 m respectively. Find the focal length of the lens and the power of the lens RI of the material of the lens-1.6.?
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The radii of curvature of two faces of a biconvex lens are 0.2 m and 0...
Given:
- Radii of curvature of the two faces of the biconvex lens: r1 = 0.2 m, r2 = 0.25 m
- Refractive index of the material of the lens: n = 1.6

To find:
- Focal length of the lens
- Power of the lens

Formula:
- The focal length of a lens can be calculated using the lens maker's formula:
1/f = (n - 1) * ((1/r1) - (1/r2))
- The power of a lens is given by the formula:
P = 1/f

Calculation:
Focal length of the lens:
- Substitute the given values into the lens maker's formula:
1/f = (1.6 - 1) * ((1/0.2) - (1/0.25))
- Simplifying the equation:
1/f = 0.6 * (5 - 4) = 0.6 * 1 = 0.6
- Taking the reciprocal of both sides:
f = 1/0.6 = 1.67 m

Therefore, the focal length of the lens is 1.67 m.

Power of the lens:
- Substitute the value of the focal length into the power formula:
P = 1/f = 1/1.67 = 0.6 diopters

Therefore, the power of the lens is 0.6 diopters.

Conclusion:
The focal length of the biconvex lens is 1.67 m and the power of the lens is 0.6 diopters.
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The radii of curvature of two faces of a biconvex lens are 0.2 m and 0.25 m respectively. Find the focal length of the lens and the power of the lens RI of the material of the lens-1.6.?
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