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What would be the magnitude and direction of average voltage induced across the field coils of a 6-pole DC generator each having 500 turns if there is a magnetic flux of 0.03 Wb/pole when the field is excited and residual magnetism of 0.003 Wb/pole after the field circuit is a is opened in 0.02 second? Consider the field coils to be connected in series.
  • a)
    24300 V and its direction is opposite to the initial direction of exciting current.
  • b)
    486 V and its direction is opposite to the initial direction of exciting current.
  • c)
    486 V and its direction is same as the initial direction of exciting current.
  • d)
    24300 V and its direction is same as the initial direction of exciting current.
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
What would be the magnitude and direction of average voltage induced a...
Given
P = Number of poles = 6
N = Total turns = 6 × 500 = 3000 (since 500 turns per pole in series)
Total initial flux = 6 × 0.03 = 0.18 Wb. (since number of poles is 6)
Total residual flux = 6 × 0.003 = 0.018 Wb
Change in flux, dϕ = 0.18 - 0.018 = 0.162 Wb
Time of opening of circuit, dt = 0.02 second
From concept,
Induced EMF (E) = 
= 24300 V
Its direction is the same as the initial direction of the exciting current.
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Community Answer
What would be the magnitude and direction of average voltage induced a...
To find the magnitude and direction of the average voltage induced across the field coils of a 6-pole DC generator, we can use Faraday's law of electromagnetic induction.

Given data:
Number of turns in each field coil (N) = 500
Magnetic flux when the field is excited (Φ1) = 0.03 Wb/pole
Magnetic flux after the field circuit is opened (Φ2) = 0.003 Wb/pole
Time taken for the field circuit to be opened (t) = 0.02 seconds

Using Faraday's law of electromagnetic induction, the average induced voltage (V) across the field coils can be calculated as:

V = -N * ΔΦ/Δt

Where:
N = number of turns in each field coil
ΔΦ = change in magnetic flux
Δt = change in time

Now let's calculate the change in magnetic flux:

ΔΦ = Φ2 - Φ1
= 0.003 Wb/pole - 0.03 Wb/pole
= -0.027 Wb/pole

Next, we calculate the change in time:

Δt = t
= 0.02 seconds

Substituting the values into the formula, we get:

V = -N * ΔΦ/Δt
= -500 * (-0.027 Wb/pole) / (0.02 seconds)
= 500 * 0.027 Wb/pole / 0.02 seconds
= 675 V

Therefore, the magnitude of the average voltage induced across the field coils is 675 V.

Now, let's determine the direction of the induced voltage. Since the magnetic flux is decreasing (from Φ1 to Φ2), the induced voltage will be in a direction opposite to the initial direction of the exciting current.

Hence, the correct answer is option 'D': 24300 V and its direction is the same as the initial direction of the exciting current.
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What would be the magnitude and direction of average voltage induced across the field coils of a 6-pole DC generator each having 500 turns if there is a magnetic flux of 0.03 Wb/pole when the field is excited and residual magnetism of 0.003 Wb/pole after the field circuit is a is opened in 0.02 second? Consider the field coils to be connected in series.a)24300 V and its direction is opposite to the initial direction of exciting current.b)486 V and its direction is opposite to the initial direction of exciting current.c)486 V and its direction is same as the initial direction of exciting current.d)24300 V and its direction is same as the initial direction of exciting current.Correct answer is option 'D'. Can you explain this answer?
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What would be the magnitude and direction of average voltage induced across the field coils of a 6-pole DC generator each having 500 turns if there is a magnetic flux of 0.03 Wb/pole when the field is excited and residual magnetism of 0.003 Wb/pole after the field circuit is a is opened in 0.02 second? Consider the field coils to be connected in series.a)24300 V and its direction is opposite to the initial direction of exciting current.b)486 V and its direction is opposite to the initial direction of exciting current.c)486 V and its direction is same as the initial direction of exciting current.d)24300 V and its direction is same as the initial direction of exciting current.Correct answer is option 'D'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about What would be the magnitude and direction of average voltage induced across the field coils of a 6-pole DC generator each having 500 turns if there is a magnetic flux of 0.03 Wb/pole when the field is excited and residual magnetism of 0.003 Wb/pole after the field circuit is a is opened in 0.02 second? Consider the field coils to be connected in series.a)24300 V and its direction is opposite to the initial direction of exciting current.b)486 V and its direction is opposite to the initial direction of exciting current.c)486 V and its direction is same as the initial direction of exciting current.d)24300 V and its direction is same as the initial direction of exciting current.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What would be the magnitude and direction of average voltage induced across the field coils of a 6-pole DC generator each having 500 turns if there is a magnetic flux of 0.03 Wb/pole when the field is excited and residual magnetism of 0.003 Wb/pole after the field circuit is a is opened in 0.02 second? Consider the field coils to be connected in series.a)24300 V and its direction is opposite to the initial direction of exciting current.b)486 V and its direction is opposite to the initial direction of exciting current.c)486 V and its direction is same as the initial direction of exciting current.d)24300 V and its direction is same as the initial direction of exciting current.Correct answer is option 'D'. Can you explain this answer?.
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