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Let X1and X2be two independent exponentially distributed random variables with means 0.5 and 0.25, respectively. Then Y = min (X1, X2) isa)exponentially distributed with mean 1⁄6b)exponentially distributed with mean 2c)normally distributed with mean 3⁄4d)normally distributed with mean 1⁄6Correct answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Let X1and X2be two independent exponentially distributed random variables with means 0.5 and 0.25, respectively. Then Y = min (X1, X2) isa)exponentially distributed with mean 1⁄6b)exponentially distributed with mean 2c)normally distributed with mean 3⁄4d)normally distributed with mean 1⁄6Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let X1and X2be two independent exponentially distributed random variables with means 0.5 and 0.25, respectively. Then Y = min (X1, X2) isa)exponentially distributed with mean 1⁄6b)exponentially distributed with mean 2c)normally distributed with mean 3⁄4d)normally distributed with mean 1⁄6Correct answer is option 'A'. Can you explain this answer?.

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