A's monthly income is 20% more than B's monthly income. B's income is ...
Let's solve this problem step by step:
Step 1: Let's assume B's monthly income as 'x'.
Step 2: We are given that A's monthly income is 20% more than B's monthly income. So, A's monthly income will be x + 20% of x, which can be written as x + (20/100)x = x + 0.2x = 1.2x.
Step 3: We are also given that B's income is 30% of C's income. So, B's monthly income is 30% of C's monthly income, which can be written as (30/100)C = 0.3C.
Step 4: The total gross monthly income of A, B, and C is given as 74700. So, we have the equation A + B + C = 74700.
Step 5: Substituting the values of A and B from step 2 and 3 into the equation from step 4, we get:
1.2x + 0.3C + C = 74700.
Step 6: Simplifying the equation, we get:
1.2x + 1.3C = 74700.
Step 7: Since we need to find the value of C, we can rearrange the equation as:
1.3C = 74700 - 1.2x.
Step 8: Now, let's assume a value for x. For example, let's assume x = 1000.
Step 9: Substituting the value of x into the rearranged equation from step 7, we get:
1.3C = 74700 - 1.2(1000) = 74700 - 1200 = 73500.
Step 10: Solving for C, we divide both sides of the equation by 1.3:
C = 73500 / 1.3 = 56538.46.
Step 11: So, the value of C, which represents the monthly income of C, is approximately 56538.46.
Therefore, the correct answer is B) 45000 Rs, as it is the closest option to the calculated value of C.
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