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Consider the sequence 8A + 2B, 6A + B, 4A, 2A – B, ........ Which term of this sequence will have a coefficient of A which is twice the coefficient of B?
- a)10th
- b)14th
- c)17th
- d)none
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
Consider the sequence 8A + 2B, 6A + B, 4A, 2A – B, ........ Whic...
coefficient of A in nth term = 8 + (n – 1)(– 2)
= 10 – 2n
coefficient of B in nth term = 2 + (n – 1)(– 1)
= 3 – n
10 – 2n = 2(3 – n) ⇒ 10 = 6
which is absurd ⇒ none
= 10 – 2n
coefficient of B in nth term = 2 + (n – 1)(– 1)
= 3 – n
10 – 2n = 2(3 – n) ⇒ 10 = 6
which is absurd ⇒ none
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Community Answer
Consider the sequence 8A + 2B, 6A + B, 4A, 2A – B, ........ Whic...
Based on the given sequence, we can see a pattern:
8A, 2B, 6A, B, 4A, 2A
From this pattern, we can observe that the sequence alternates between a number followed by a letter, and then just a number.
If we continue the pattern, the next term would be:
A
Therefore, the next term in the sequence is A.
8A, 2B, 6A, B, 4A, 2A
From this pattern, we can observe that the sequence alternates between a number followed by a letter, and then just a number.
If we continue the pattern, the next term would be:
A
Therefore, the next term in the sequence is A.
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Consider the sequence 8A + 2B, 6A + B, 4A, 2A – B, ........ Which term of this sequence will have a coefficient of A which is twice the coefficient of B?a)10thb)14thc)17thd)noneCorrect answer is option 'D'. Can you explain this answer?
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