The displacement equation for a particle executing SHM is y=0.2sin50pi...
Displacement of a Particle Executing SHM
The displacement equation for a particle executing SHM is given by:
y = 0.2 sin(50πt + 0.01)m
Explanation of the Equation
- The amplitude of the SHM is 0.2m.
- The frequency of the SHM is 50Hz.
- The phase constant is 0.01 radians.
- t is the time elapsed in seconds.
Calculation of Displacement at Start of Motion
The displacement of the particle at the start of motion is the value of y when t = 0.
y = 0.2 sin(50π(0) + 0.01)m
y = 0.2 sin(0.01)m
y = 0.002m
Explanation of Displacement at Start of Motion
The displacement at the start of motion is given by the amplitude of the SHM, which is 0.2m, multiplied by the sine of the phase constant, which is 0.01 radians.
Since sine of 0.01 radians is a very small value, the displacement at the start of motion is also very small, i.e., 0.002m. This means that the particle is very close to its equilibrium position at the start of motion.