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The displacement equation for a particle executing SHM is y=0.2sin50pi(t+0.01)m where y is the displacement at instant calculate the displacement at the start of motion ?
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The displacement equation for a particle executing SHM is y=0.2sin50pi...
Dear kencho dorji, I have a solution for it hope u understand....Displacement at the start of motion (yo)=   0.2sin50π((t=0)+0.01) m =  0.2sin50π(0.01) m =   0.2sin(0.5π) m = 0.2 sin(90) = 0.2 mRegards.
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The displacement equation for a particle executing SHM is y=0.2sin50pi...
Displacement of a Particle Executing SHM


The displacement equation for a particle executing SHM is given by:


y = 0.2 sin(50πt + 0.01)m


Explanation of the Equation



  • The amplitude of the SHM is 0.2m.

  • The frequency of the SHM is 50Hz.

  • The phase constant is 0.01 radians.

  • t is the time elapsed in seconds.



Calculation of Displacement at Start of Motion


The displacement of the particle at the start of motion is the value of y when t = 0.


y = 0.2 sin(50π(0) + 0.01)m


y = 0.2 sin(0.01)m


y = 0.002m


Explanation of Displacement at Start of Motion


The displacement at the start of motion is given by the amplitude of the SHM, which is 0.2m, multiplied by the sine of the phase constant, which is 0.01 radians.


Since sine of 0.01 radians is a very small value, the displacement at the start of motion is also very small, i.e., 0.002m. This means that the particle is very close to its equilibrium position at the start of motion.
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