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The work done is ‘0’ if
- a)The body shows displacement in the opposite direction of the force applied.
- b)The body shows displacement in the same direction as that of the force applied.
- c)The body shows a displacement in perpendicular direction to the force applied.
- d)The body masses obliquely to the direction of the force applied.
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The work done is ‘0’ ifa)The body shows displacement in th...
Explanation:
The work done on a body is defined as the product of the force applied on the body and the displacement of the body in the direction of the force. In this case, the work done is '0', which means there is no net transfer of energy to or from the body.
To understand why the work done is '0', let's consider the options one by one:
A: The body shows displacement in the opposite direction of the force applied.
- In this case, the work done will be negative because the displacement is in the opposite direction of the force. So, option A is not correct.
B: The body shows displacement in the same direction as that of the force applied.
- In this case, the work done will be positive because the displacement is in the same direction as the force. So, option B is not correct.
C: The body shows a displacement in perpendicular direction to the force applied.
- In this case, the work done will be zero because the displacement is perpendicular to the force. This means that there is no component of the force in the direction of displacement, and hence no work is done. So, option C is correct.
D: The body masses obliquely to the direction of the force applied.
- This option is not clear and seems to have a typographical error. It is difficult to understand what is meant by "the body masses obliquely to the direction of the force applied". Therefore, option D is not a valid option.
Thus, the correct answer is option C: The body shows a displacement in perpendicular direction to the force applied.
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The work done on a body is defined as the product of the force applied on the body and the displacement of the body in the direction of the force. In this case, the work done is '0', which means there is no net transfer of energy to or from the body.
To understand why the work done is '0', let's consider the options one by one:
A: The body shows displacement in the opposite direction of the force applied.
- In this case, the work done will be negative because the displacement is in the opposite direction of the force. So, option A is not correct.
B: The body shows displacement in the same direction as that of the force applied.
- In this case, the work done will be positive because the displacement is in the same direction as the force. So, option B is not correct.
C: The body shows a displacement in perpendicular direction to the force applied.
- In this case, the work done will be zero because the displacement is perpendicular to the force. This means that there is no component of the force in the direction of displacement, and hence no work is done. So, option C is correct.
D: The body masses obliquely to the direction of the force applied.
- This option is not clear and seems to have a typographical error. It is difficult to understand what is meant by "the body masses obliquely to the direction of the force applied". Therefore, option D is not a valid option.
Thus, the correct answer is option C: The body shows a displacement in perpendicular direction to the force applied.
Most Upvoted Answer
The work done is ‘0’ ifa)The body shows displacement in th...
The amount of energy transferred by a force acting on an object over a distance. It is a scalar quantity and is measured in joules (J). The formula to calculate work done is:
Work = Force x Distance x cosine(theta)
where Force is the magnitude of the force applied, Distance is the displacement of the object, and theta is the angle between the force and the displacement vectors.
Work can be positive, negative, or zero depending on the direction of the force and the displacement. Positive work is done when the force and displacement are in the same direction, negative work is done when they are in opposite directions, and zero work is done when there is no displacement or no force applied.
Work = Force x Distance x cosine(theta)
where Force is the magnitude of the force applied, Distance is the displacement of the object, and theta is the angle between the force and the displacement vectors.
Work can be positive, negative, or zero depending on the direction of the force and the displacement. Positive work is done when the force and displacement are in the same direction, negative work is done when they are in opposite directions, and zero work is done when there is no displacement or no force applied.
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The work done is ‘0’ ifa)The body shows displacement in the opposite direction of the force applied.b)The body shows displacement in the same direction as that of the force applied.c)The body shows a displacement in perpendicular direction to the force applied.d)The body masses obliquely to the direction of the force applied.Correct answer is option 'C'. Can you explain this answer?
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