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P and Q are two points on the base AB of a triangle ABC whose vertices are (–2, 3), (4, – 6) and (1, 1) respectively. If the join of CP and CQ divides the triangle ABC into three triangles of equal areas, then the equation of line pair through the origin and parallel to CP and CQ is equal toa)y2 + 4xy – 3x2 = 0b)3y2 +4xy +x2 = 0c)y2 + 3xy – 4x2 = 0d)y2 – 5xy + 4x2 = 0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about P and Q are two points on the base AB of a triangle ABC whose vertices are (–2, 3), (4, – 6) and (1, 1) respectively. If the join of CP and CQ divides the triangle ABC into three triangles of equal areas, then the equation of line pair through the origin and parallel to CP and CQ is equal toa)y2 + 4xy – 3x2 = 0b)3y2 +4xy +x2 = 0c)y2 + 3xy – 4x2 = 0d)y2 – 5xy + 4x2 = 0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for P and Q are two points on the base AB of a triangle ABC whose vertices are (–2, 3), (4, – 6) and (1, 1) respectively. If the join of CP and CQ divides the triangle ABC into three triangles of equal areas, then the equation of line pair through the origin and parallel to CP and CQ is equal toa)y2 + 4xy – 3x2 = 0b)3y2 +4xy +x2 = 0c)y2 + 3xy – 4x2 = 0d)y2 – 5xy + 4x2 = 0Correct answer is option 'C'. Can you explain this answer?.

Solutions for P and Q are two points on the base AB of a triangle ABC whose vertices are (–2, 3), (4, – 6) and (1, 1) respectively. If the join of CP and CQ divides the triangle ABC into three triangles of equal areas, then the equation of line pair through the origin and parallel to CP and CQ is equal toa)y2 + 4xy – 3x2 = 0b)3y2 +4xy +x2 = 0c)y2 + 3xy – 4x2 = 0d)y2 – 5xy + 4x2 = 0Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of P and Q are two points on the base AB of a triangle ABC whose vertices are (–2, 3), (4, – 6) and (1, 1) respectively. If the join of CP and CQ divides the triangle ABC into three triangles of equal areas, then the equation of line pair through the origin and parallel to CP and CQ is equal toa)y2 + 4xy – 3x2 = 0b)3y2 +4xy +x2 = 0c)y2 + 3xy – 4x2 = 0d)y2 – 5xy + 4x2 = 0Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of P and Q are two points on the base AB of a triangle ABC whose vertices are (–2, 3), (4, – 6) and (1, 1) respectively. If the join of CP and CQ divides the triangle ABC into three triangles of equal areas, then the equation of line pair through the origin and parallel to CP and CQ is equal toa)y2 + 4xy – 3x2 = 0b)3y2 +4xy +x2 = 0c)y2 + 3xy – 4x2 = 0d)y2 – 5xy + 4x2 = 0Correct answer is option 'C'. Can you explain this answer?, a detailed solution for P and Q are two points on the base AB of a triangle ABC whose vertices are (–2, 3), (4, – 6) and (1, 1) respectively. If the join of CP and CQ divides the triangle ABC into three triangles of equal areas, then the equation of line pair through the origin and parallel to CP and CQ is equal toa)y2 + 4xy – 3x2 = 0b)3y2 +4xy +x2 = 0c)y2 + 3xy – 4x2 = 0d)y2 – 5xy + 4x2 = 0Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of P and Q are two points on the base AB of a triangle ABC whose vertices are (–2, 3), (4, – 6) and (1, 1) respectively. If the join of CP and CQ divides the triangle ABC into three triangles of equal areas, then the equation of line pair through the origin and parallel to CP and CQ is equal toa)y2 + 4xy – 3x2 = 0b)3y2 +4xy +x2 = 0c)y2 + 3xy – 4x2 = 0d)y2 – 5xy + 4x2 = 0Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice P and Q are two points on the base AB of a triangle ABC whose vertices are (–2, 3), (4, – 6) and (1, 1) respectively. If the join of CP and CQ divides the triangle ABC into three triangles of equal areas, then the equation of line pair through the origin and parallel to CP and CQ is equal toa)y2 + 4xy – 3x2 = 0b)3y2 +4xy +x2 = 0c)y2 + 3xy – 4x2 = 0d)y2 – 5xy + 4x2 = 0Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.