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0.144 g of pure FeC2O4 was dissolved in dilute H2SO4 and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4 will be needed to oxidise FeC2O4 solution?
Correct answer is '6'. Can you explain this answer?
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0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution wa...
Solution:
Given:
Mass of pure FeC2O4 = 0.144 g
Volume of solution = 100 ml
Concentration of KMnO4 = 0.1 M
To find:
Volume of 0.1 M KMnO4 required to oxidize FeC2O4 solution
Step 1: Calculate the number of moles of FeC2O4
We know that the molar mass of FeC2O4 = 55.85 + 2(12.01) + 4(16.00) = 179.85 g/mol
Number of moles of FeC2O4 = Mass of FeC2O4 / Molar mass of FeC2O4
= 0.144 g / 179.85 g/mol
= 0.000801 mol
Step 2: Calculate the number of moles of KMnO4 required for oxidation
The balanced chemical equation for the reaction between FeC2O4 and KMnO4 is:
5FeC2O4 + KMnO4 + 8H2SO4 -> 5FeSO4 + 2MnSO4 + 10CO2 + 8H2O + K2SO4
From the balanced equation, we can see that 5 moles of FeC2O4 react with 1 mole of KMnO4.
So, the number of moles of KMnO4 required = 0.000801 mol / 5
= 0.0001602 mol
Step 3: Calculate the volume of 0.1 M KMnO4 required
We can use the equation:
Moles = Concentration x Volume
Volume = Moles / Concentration
Volume of 0.1 M KMnO4 required = 0.0001602 mol / 0.1 mol/L
= 0.001602 L = 1.602 ml
Therefore, the volume of 0.1 M KMnO4 required to oxidize the FeC2O4 solution is 1.602 ml.
Given:
Mass of pure FeC2O4 = 0.144 g
Volume of solution = 100 ml
Concentration of KMnO4 = 0.1 M
To find:
Volume of 0.1 M KMnO4 required to oxidize FeC2O4 solution
Step 1: Calculate the number of moles of FeC2O4
We know that the molar mass of FeC2O4 = 55.85 + 2(12.01) + 4(16.00) = 179.85 g/mol
Number of moles of FeC2O4 = Mass of FeC2O4 / Molar mass of FeC2O4
= 0.144 g / 179.85 g/mol
= 0.000801 mol
Step 2: Calculate the number of moles of KMnO4 required for oxidation
The balanced chemical equation for the reaction between FeC2O4 and KMnO4 is:
5FeC2O4 + KMnO4 + 8H2SO4 -> 5FeSO4 + 2MnSO4 + 10CO2 + 8H2O + K2SO4
From the balanced equation, we can see that 5 moles of FeC2O4 react with 1 mole of KMnO4.
So, the number of moles of KMnO4 required = 0.000801 mol / 5
= 0.0001602 mol
Step 3: Calculate the volume of 0.1 M KMnO4 required
We can use the equation:
Moles = Concentration x Volume
Volume = Moles / Concentration
Volume of 0.1 M KMnO4 required = 0.0001602 mol / 0.1 mol/L
= 0.001602 L = 1.602 ml
Therefore, the volume of 0.1 M KMnO4 required to oxidize the FeC2O4 solution is 1.602 ml.
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0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer?
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0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer?.
0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer?.
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0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer?, a detailed solution for 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? has been provided alongside types of 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? theory, EduRev gives you an
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