JEE Exam > JEE Questions > 0.144 g of pure FeC2O4was dissolved in dilute...
Start Learning for Free
0.144 g of pure FeC2O4 was dissolved in dilute H2SO4 and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4 will be needed to oxidise FeC2O4 solution?
Correct answer is '6'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution wa...
Free Test
FREE
| Start Free Test |
Community Answer
0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution wa...
Solution:
Given:
Mass of pure FeC2O4 = 0.144 g
Volume of solution = 100 ml
Concentration of KMnO4 = 0.1 M
To find:
Volume of 0.1 M KMnO4 required to oxidize FeC2O4 solution
Step 1: Calculate the number of moles of FeC2O4
We know that the molar mass of FeC2O4 = 55.85 + 2(12.01) + 4(16.00) = 179.85 g/mol
Number of moles of FeC2O4 = Mass of FeC2O4 / Molar mass of FeC2O4
= 0.144 g / 179.85 g/mol
= 0.000801 mol
Step 2: Calculate the number of moles of KMnO4 required for oxidation
The balanced chemical equation for the reaction between FeC2O4 and KMnO4 is:
5FeC2O4 + KMnO4 + 8H2SO4 -> 5FeSO4 + 2MnSO4 + 10CO2 + 8H2O + K2SO4
From the balanced equation, we can see that 5 moles of FeC2O4 react with 1 mole of KMnO4.
So, the number of moles of KMnO4 required = 0.000801 mol / 5
= 0.0001602 mol
Step 3: Calculate the volume of 0.1 M KMnO4 required
We can use the equation:
Moles = Concentration x Volume
Volume = Moles / Concentration
Volume of 0.1 M KMnO4 required = 0.0001602 mol / 0.1 mol/L
= 0.001602 L = 1.602 ml
Therefore, the volume of 0.1 M KMnO4 required to oxidize the FeC2O4 solution is 1.602 ml.
Given:
Mass of pure FeC2O4 = 0.144 g
Volume of solution = 100 ml
Concentration of KMnO4 = 0.1 M
To find:
Volume of 0.1 M KMnO4 required to oxidize FeC2O4 solution
Step 1: Calculate the number of moles of FeC2O4
We know that the molar mass of FeC2O4 = 55.85 + 2(12.01) + 4(16.00) = 179.85 g/mol
Number of moles of FeC2O4 = Mass of FeC2O4 / Molar mass of FeC2O4
= 0.144 g / 179.85 g/mol
= 0.000801 mol
Step 2: Calculate the number of moles of KMnO4 required for oxidation
The balanced chemical equation for the reaction between FeC2O4 and KMnO4 is:
5FeC2O4 + KMnO4 + 8H2SO4 -> 5FeSO4 + 2MnSO4 + 10CO2 + 8H2O + K2SO4
From the balanced equation, we can see that 5 moles of FeC2O4 react with 1 mole of KMnO4.
So, the number of moles of KMnO4 required = 0.000801 mol / 5
= 0.0001602 mol
Step 3: Calculate the volume of 0.1 M KMnO4 required
We can use the equation:
Moles = Concentration x Volume
Volume = Moles / Concentration
Volume of 0.1 M KMnO4 required = 0.0001602 mol / 0.1 mol/L
= 0.001602 L = 1.602 ml
Therefore, the volume of 0.1 M KMnO4 required to oxidize the FeC2O4 solution is 1.602 ml.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer?
Question Description
0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer?.
0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer?.
Solutions for 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer?, a detailed solution for 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? has been provided alongside types of 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice 0.144 g of pure FeC2O4was dissolved in dilute H2SO4and the solution was diluted to 100 ml. What volume in ml of 0.1 M KMnO4will be needed to oxidise FeC2O4solution?Correct answer is '6'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup