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The a-decay of p0210 nuclei (in the ground state) is accompained by emission of two groups of α-particles with kinetic energies 5.30 MeV and 4.50 MeV. Following the emission of these particles the daughter nuclei are found in the ground and excited states. The energy of the gamma quanta emitted by the excited nuclei is:
  • a)
    0.80 MeV
  • b)
    9.8 MeV
  • c)
    1.6 MeV
  • d)
    2.4 MeV
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The a-decay of p0210nuclei (in the ground state) is accompained by emi...
  • In α-decay, the initial nucleus decays into an alpha particle and a daughter nucleus. The daughter nucleus can initially be in an excited state and then it transitions to a lower energy state (often the ground state) by emission of a gamma photon.
  • In this case, we've been given two groups of α-particles with kinetic energies of 5.30 MeV and 4.50 MeV. This implies corresponding transitions to two different states (an excited state and the ground state) in the daughter nuclei.
  • The energy level difference between the ground and excited state of the daughter nucleus is equal to the energy difference of the two α-particles, which is: 5.30 MeV - 4.50 MeV = 0.80 MeV.
  • This difference in energy would be carried away by a gamma photon when the excited daughter nucleus transitions to the ground state. This matches option: 0.80 MeV. So the energy of gamma quanta emitted by the excited nuclei is 0.80 MeV.
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The a-decay of p0210nuclei (in the ground state) is accompained by emission of two groups of α-particles with kinetic energies 5.30 MeV and 4.50 MeV. Following the emission of these particles the daughter nuclei are found in the ground and excited states. The energy of the gamma quanta emitted by the excited nuclei is:a)0.80 MeVb)9.8 MeVc)1.6 MeVd)2.4 MeVCorrect answer is option 'A'. Can you explain this answer?
Question Description
The a-decay of p0210nuclei (in the ground state) is accompained by emission of two groups of α-particles with kinetic energies 5.30 MeV and 4.50 MeV. Following the emission of these particles the daughter nuclei are found in the ground and excited states. The energy of the gamma quanta emitted by the excited nuclei is:a)0.80 MeVb)9.8 MeVc)1.6 MeVd)2.4 MeVCorrect answer is option 'A'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The a-decay of p0210nuclei (in the ground state) is accompained by emission of two groups of α-particles with kinetic energies 5.30 MeV and 4.50 MeV. Following the emission of these particles the daughter nuclei are found in the ground and excited states. The energy of the gamma quanta emitted by the excited nuclei is:a)0.80 MeVb)9.8 MeVc)1.6 MeVd)2.4 MeVCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The a-decay of p0210nuclei (in the ground state) is accompained by emission of two groups of α-particles with kinetic energies 5.30 MeV and 4.50 MeV. Following the emission of these particles the daughter nuclei are found in the ground and excited states. The energy of the gamma quanta emitted by the excited nuclei is:a)0.80 MeVb)9.8 MeVc)1.6 MeVd)2.4 MeVCorrect answer is option 'A'. Can you explain this answer?.
Solutions for The a-decay of p0210nuclei (in the ground state) is accompained by emission of two groups of α-particles with kinetic energies 5.30 MeV and 4.50 MeV. Following the emission of these particles the daughter nuclei are found in the ground and excited states. The energy of the gamma quanta emitted by the excited nuclei is:a)0.80 MeVb)9.8 MeVc)1.6 MeVd)2.4 MeVCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for UGC NET. Download more important topics, notes, lectures and mock test series for UGC NET Exam by signing up for free.
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