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An organic compound contain 10.4% C, 0.84%H & 89.12%Cl. Find out empirical formula and molecular formula is molar mass = 119.5 g?
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An organic compound contain 10.4% C, 0.84%H & 89.12%Cl. Find out empi...
To find the empirical formula of the organic compound, we need to determine the ratio of carbon to hydrogen atoms.
Given:
% C = 10.4%
% H = 0.84%
Assuming we have 100g of the compound, we can calculate the mass of carbon and hydrogen:
Mass of carbon = 10.4g
Mass of hydrogen = 0.84g
Next, we need to convert the mass of carbon and hydrogen to moles by dividing by their respective atomic masses:
Atomic mass of carbon (C) = 12.01 g/mol
Atomic mass of hydrogen (H) = 1.01 g/mol
Moles of carbon = 10.4g / 12.01 g/mol ≈ 0.866 mol
Moles of hydrogen = 0.84g / 1.01 g/mol ≈ 0.832 mol
Now, we need to find the simplest whole number ratio between carbon and hydrogen. We can divide both moles by the smaller value (0.832 mol):
Moles of carbon (C) = 0.866 mol / 0.832 mol ≈ 1.04
Moles of hydrogen (H) = 0.832 mol / 0.832 mol ≈ 1
The ratio of carbon to hydrogen is approximately 1:1.
Therefore, the empirical formula of the organic compound is CH.
Given:
% C = 10.4%
% H = 0.84%
Assuming we have 100g of the compound, we can calculate the mass of carbon and hydrogen:
Mass of carbon = 10.4g
Mass of hydrogen = 0.84g
Next, we need to convert the mass of carbon and hydrogen to moles by dividing by their respective atomic masses:
Atomic mass of carbon (C) = 12.01 g/mol
Atomic mass of hydrogen (H) = 1.01 g/mol
Moles of carbon = 10.4g / 12.01 g/mol ≈ 0.866 mol
Moles of hydrogen = 0.84g / 1.01 g/mol ≈ 0.832 mol
Now, we need to find the simplest whole number ratio between carbon and hydrogen. We can divide both moles by the smaller value (0.832 mol):
Moles of carbon (C) = 0.866 mol / 0.832 mol ≈ 1.04
Moles of hydrogen (H) = 0.832 mol / 0.832 mol ≈ 1
The ratio of carbon to hydrogen is approximately 1:1.
Therefore, the empirical formula of the organic compound is CH.
Community Answer
An organic compound contain 10.4% C, 0.84%H & 89.12%Cl. Find out empi...
Is it CHCl3 for both.....?
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An organic compound contain 10.4% C, 0.84%H & 89.12%Cl. Find out empirical formula and molecular formula is molar mass = 119.5 g?
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An organic compound contain 10.4% C, 0.84%H & 89.12%Cl. Find out empirical formula and molecular formula is molar mass = 119.5 g? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An organic compound contain 10.4% C, 0.84%H & 89.12%Cl. Find out empirical formula and molecular formula is molar mass = 119.5 g? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound contain 10.4% C, 0.84%H & 89.12%Cl. Find out empirical formula and molecular formula is molar mass = 119.5 g?.
An organic compound contain 10.4% C, 0.84%H & 89.12%Cl. Find out empirical formula and molecular formula is molar mass = 119.5 g? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An organic compound contain 10.4% C, 0.84%H & 89.12%Cl. Find out empirical formula and molecular formula is molar mass = 119.5 g? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound contain 10.4% C, 0.84%H & 89.12%Cl. Find out empirical formula and molecular formula is molar mass = 119.5 g?.
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