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What should be the minimum energy of a photon for it to split an ∝ particle at rest into a tritium and a proton? (The masses of  are 4.0026 amu, 3.0161 amu and 1.0073 amu, respectively, and 1 amu ≈938MeV.)
  • a)
    19.3 MeV
  • b)
    3 MeV
  • c)
     
    931.5 MeV
  • d)
     
    32.2 MeV
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
What should be the minimum energy of a photon for it to split an∝...
Here, a photon splits an ∝ - particle at rest into a tritium and a proton. The reaction may be given as,

Therefore, the energy of the photon will be minimum only if the tritium and created at rest.
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What should be the minimum energy of a photon for it to split an∝particle at rest into a tritium and a proton? (The masses ofare4.0026amu,3.0161amu and1.0073amu, respectively, and1amu≈938MeV.)a)19.3MeVb)3MeVc)931.5MeVd)32.2MeVCorrect answer is option 'A'. Can you explain this answer?
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What should be the minimum energy of a photon for it to split an∝particle at rest into a tritium and a proton? (The masses ofare4.0026amu,3.0161amu and1.0073amu, respectively, and1amu≈938MeV.)a)19.3MeVb)3MeVc)931.5MeVd)32.2MeVCorrect answer is option 'A'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about What should be the minimum energy of a photon for it to split an∝particle at rest into a tritium and a proton? (The masses ofare4.0026amu,3.0161amu and1.0073amu, respectively, and1amu≈938MeV.)a)19.3MeVb)3MeVc)931.5MeVd)32.2MeVCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What should be the minimum energy of a photon for it to split an∝particle at rest into a tritium and a proton? (The masses ofare4.0026amu,3.0161amu and1.0073amu, respectively, and1amu≈938MeV.)a)19.3MeVb)3MeVc)931.5MeVd)32.2MeVCorrect answer is option 'A'. Can you explain this answer?.
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