Class 11 Exam > Class 11 Questions > It's given that, T stands for time period; L ...
Start Learning for Free
It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct?
Most Upvoted Answer
It's given that, T stands for time period; L stands for length; of a s...
The relation T^2 = l/g is dimensionally correct. The thing that you might be confusing is that "All correct physically plausible relations must always be dimensionally correct but all dimensionally correct relations need not be the exact physical relation between two physical quantities." It should be determined experimentally, or if enough physical laws are known, should be deduced based on it.Further, as an example v^2 = u ^2 + a*s , where v, u, a and s are respectively velocity, initial velocity, acceleration and displacement is a dimensionally correct relation but not the exact relationship between these variables.
Community Answer
It's given that, T stands for time period; L stands for length; of a s...
Relation between Time Period and Length of a Simple Pendulum
Understanding the Relationship
- The time period (T) of a simple pendulum is the time taken for one complete oscillation.
- The length (L) of the pendulum and the acceleration due to gravity (g) are two key factors that affect the time period.
Mathematical Relation
- The formula for the time period of a simple pendulum is given by T = 2π√(L/g).
- Squaring both sides of the equation gives T^2 = 4π^2(L/g).
Verification of the Relation T^2 = (1/g)
- If we substitute T^2 = 4π^2(L/g) into T^2 = (1/g), we get 4π^2(L/g) = (1/g).
- By simplifying the equation, we get 4π^2L = 1.
- Since there is no g on the left-hand side of the equation, it is evident that the relation T^2 = (1/g) is incorrect.
Conclusion
- The correct relation between the time period and acceleration due to gravity is T^2 = 4π^2(L/g), as derived from the formula for the time period of a simple pendulum. It is essential to use the accurate formula to calculate the time period correctly in physics experiments involving pendulums.
Understanding the Relationship
- The time period (T) of a simple pendulum is the time taken for one complete oscillation.
- The length (L) of the pendulum and the acceleration due to gravity (g) are two key factors that affect the time period.
Mathematical Relation
- The formula for the time period of a simple pendulum is given by T = 2π√(L/g).
- Squaring both sides of the equation gives T^2 = 4π^2(L/g).
Verification of the Relation T^2 = (1/g)
- If we substitute T^2 = 4π^2(L/g) into T^2 = (1/g), we get 4π^2(L/g) = (1/g).
- By simplifying the equation, we get 4π^2L = 1.
- Since there is no g on the left-hand side of the equation, it is evident that the relation T^2 = (1/g) is incorrect.
Conclusion
- The correct relation between the time period and acceleration due to gravity is T^2 = 4π^2(L/g), as derived from the formula for the time period of a simple pendulum. It is essential to use the accurate formula to calculate the time period correctly in physics experiments involving pendulums.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Top Courses for Class 11View all
It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct?
Question Description
It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct?.
It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct?.
Solutions for It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct? defined & explained in the simplest way possible. Besides giving the explanation of
It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct?, a detailed solution for It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct? has been provided alongside types of It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct? theory, EduRev gives you an
ample number of questions to practice It's given that, T stands for time period; L stands for length; of a simple pendulum. If "g" is the acceleration due to gravity, then is the relation "T^2 = (1/g) correct? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup