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The input Vt to the following circuit is a square wave as shown in the following figure.

Which of the waveforms best describes the output?
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The input Vt to the following circuit is a square wave as shown in the...
Concept:
A differentiator circuit is an electronic circuit that is used to differentiate a voltage input signal with respect to time. The output voltage of the circuit is proportional to the rate of change of the input voltage. The circuit is typically constructed using an operational amplifier (op-amp) and a capacitor. The capacitor allows changes in the input voltage to pass through to the op-amp, which amplifies the signal and produces an output voltage that is proportional to the rate of change of the input voltage. The circuit is often used in applications such as signal processing and control systems, where it is necessary to measure the rate of change of a voltage signal. However, differentiator circuits are sensitive to high-frequency noise and can generate significant noise at the output, so care must be taken in their design and use. In addition, the high gain of the op-amp can lead to instability and oscillation if the circuit is not properly designed and compensated.
Explanation:
We are given a differentiator circuit here with input as a square waveform, which is shown below:

In the input signal is discontinuous at end of the peaks of the square signal.
Those are not differentiable, hence there will be sudden spikes there.
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The input Vt to the following circuit is a square wave as shown in the following figure.Which of the waveforms best describes the output?a)b)c)d)Correct answer is option 'C'. Can you explain this answer?
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