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A beam, 600 mm deep and 250 mm wide, is subjected to shear force and torsional moment of 160 kN and 40 kNm. The equivalent shear is,
  • a)
    465 kN
  • b)
    416 kN
  • c)
    513 kN
  • d)
    345 kN
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A beam, 600 mm deep and 250 mm wide, is subjected to shear force and t...
As per IS 456:2000, Cl.41.3-
Equivalent shear (Ve)
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Community Answer
A beam, 600 mm deep and 250 mm wide, is subjected to shear force and t...
Given data:
- Depth of the beam (d) = 600 mm
- Width of the beam (b) = 250 mm
- Shear force (V) = 160 kN
- Torsional moment (T) = 40 kNm

Calculating the equivalent shear:
- The formula to calculate the equivalent shear is given by:
V_eq = V + (T * (b/2) / (d * b))
- Substituting the given values:
V_eq = 160 + (40 * (250/2) / (600 * 250))
V_eq = 160 + (40 * 125 / 150000)
V_eq = 160 + (5000 / 150000)
V_eq = 160 + 0.0333
V_eq = 160.033 kN
Therefore, the equivalent shear force is 416 kN (approximately).

Conclusion:
The correct answer is option 'B', 416 kN.
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