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A body of mass 2 kg and Cp = 1.00 kj/Kg K is available at 600 K. If the atmosphere is 300 K and In 2=0.693, the maximum work obtainable from the body till it comes to equilibrium with the atmosphere is
  • a)
    150 kJ
  • b)
    142 kJ
  • c)
    184.2 kJ
  • d)
    190.5 kJ
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A body of mass 2 kg and Cp = 1.00 kj/Kg K is available at 600 K. If t...
Given:
Mass of the body (m) = 2 kg
Specific heat capacity (Cp) = 1.00 kJ/kg K
Temperature of the body (T1) = 600 K
Temperature of the atmosphere (T2) = 300 K
Value of In 2 (natural logarithm of 2) = 0.693

To Find:
The maximum work obtainable from the body until it comes to equilibrium with the atmosphere.

Assumptions:
- The process is assumed to be reversible and adiabatic.
- The specific heat capacity remains constant throughout the process.
- The body is in thermal equilibrium with the atmosphere at the end of the process.

Formula:
The work done during an adiabatic process can be calculated using the formula:
W = Cp * m * (T1 - T2)

Calculation:
Substituting the given values into the formula, we get:
W = 1.00 kJ/kg K * 2 kg * (600 K - 300 K)
W = 1.00 kJ/kg K * 2 kg * 300 K
W = 600 kJ

However, this is not the maximum work obtainable from the body. To find the maximum work, we need to consider the change in entropy.

Entropy Calculation:
Change in entropy (ΔS) can be calculated using the formula:
ΔS = Cp * ln(T1/T2)

Substituting the given values into the formula, we get:
ΔS = 1.00 kJ/kg K * ln(600 K / 300 K)
ΔS = 1.00 kJ/kg K * ln(2)
ΔS = 1.00 kJ/kg K * 0.693
ΔS = 0.693 kJ/kg

The maximum work obtainable from the body can be calculated using the formula:
Wmax = T1 * ΔS

Substituting the values, we get:
Wmax = 600 K * 0.693 kJ/kg
Wmax = 415.8 kJ

Therefore, the maximum work obtainable from the body until it comes to equilibrium with the atmosphere is approximately 415.8 kJ.
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A body of mass 2 kg and Cp = 1.00 kj/Kg K is available at 600 K. If the atmosphere is 300 K and In 2=0.693, the maximum work obtainable from the body till it comes to equilibrium with the atmosphere isa)150 kJb)142 kJc)184.2 kJd)190.5 kJCorrect answer is option 'C'. Can you explain this answer?
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A body of mass 2 kg and Cp = 1.00 kj/Kg K is available at 600 K. If the atmosphere is 300 K and In 2=0.693, the maximum work obtainable from the body till it comes to equilibrium with the atmosphere isa)150 kJb)142 kJc)184.2 kJd)190.5 kJCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A body of mass 2 kg and Cp = 1.00 kj/Kg K is available at 600 K. If the atmosphere is 300 K and In 2=0.693, the maximum work obtainable from the body till it comes to equilibrium with the atmosphere isa)150 kJb)142 kJc)184.2 kJd)190.5 kJCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 2 kg and Cp = 1.00 kj/Kg K is available at 600 K. If the atmosphere is 300 K and In 2=0.693, the maximum work obtainable from the body till it comes to equilibrium with the atmosphere isa)150 kJb)142 kJc)184.2 kJd)190.5 kJCorrect answer is option 'C'. Can you explain this answer?.
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