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If in equilateral triangle charges -3q,q,q are on vertices of triangle of side a.Then find dipole moment of the system.
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If in equilateral triangle charges -3q,q,q are on vertices of triangle...
Equilateral Triangle with Charges


Given Information


  • Equilateral triangle

  • Side length = a

  • Charges on each vertex = -3q, q, q



Dipole Moment

The dipole moment is defined as the product of distance and the magnitude of the charge. In this case, we can calculate the dipole moment by considering the two charges with equal magnitude and opposite sign.


The distance between these two charges can be found by drawing a line connecting the two charges through the center of the equilateral triangle. This line will be perpendicular to the base of the triangle and will bisect the angle between the two charges.


The length of this line can be found using the Pythagorean theorem:

a^2 = (a/2)^2 + d^2

where d is the distance between the two charges.


Simplifying the equation, we get:

d = a/2 * sqrt(3)


The dipole moment can be calculated using the formula:

p = q * d


For this system, we have two charges with magnitude q and distance d between them. Therefore, the dipole moment is:

p = q * d

p = q * a/2 * sqrt(3)


Since the two charges have equal magnitude, but opposite sign, the dipole moment will be in the direction of the line connecting the two charges, from the negative charge to the positive charge.


Conclusion

The dipole moment of the system of charges in an equilateral triangle with charges -3q, q, q on the vertices is q * a/2 * sqrt(3) in the direction from the negative charge to the positive charge.
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If in equilateral triangle charges -3q,q,q are on vertices of triangle...
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If in equilateral triangle charges -3q,q,q are on vertices of triangle of side a.Then find dipole moment of the system.
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