10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)(A) 0.7 (B) 1 (C) 1.88 (D) 2.88?

Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity

Open App

JEE Exam > JEE Questions > 10 mL of M/5 CH3COONa solution is titrated wi...

Join the Discussion on the App

10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)
(A) 0.7 (B) 1 (C) 1.88 (D) 2.88?

Join for Free

Join for Free

Most Upvoted Answer

10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The ...

Introduction:

In this titration, a M/5 CH3COONa solution (sodium acetate) is being titrated with a M/5 HCl solution (hydrochloric acid). The pH value at the equivalence point can be determined by considering the acid-base properties of the solutions involved and the reaction that occurs during the titration.

Equation:

The reaction between sodium acetate and hydrochloric acid can be represented by the following equation:

CH3COONa + HCl → CH3COOH + NaCl

Equivalence Point:

The equivalence point in a titration occurs when the number of moles of acid is equal to the number of moles of base or vice versa. In this case, at the equivalence point, all the sodium acetate will react with hydrochloric acid to form acetic acid and sodium chloride.

pH at Equivalence Point:

The pH at the equivalence point can be determined by considering the nature of the products formed during the reaction. Acetic acid (CH3COOH) is a weak acid and sodium chloride (NaCl) is a neutral salt.

Acetic Acid:

Acetic acid is a weak acid, meaning that it does not completely dissociate in water. It undergoes a partial ionization:

CH3COOH ⇌ CH3COO- + H+

At the equivalence point, all the sodium acetate has reacted with hydrochloric acid, resulting in the formation of acetic acid. Since acetic acid is a weak acid, the concentration of H+ ions will be relatively low.

pH Calculation:

To calculate the pH at the equivalence point, we need to consider the dissociation of water. Water undergoes self-ionization:

H2O ⇌ H+ + OH-

The concentration of H+ ions in pure water (at 25°C) is 1 x 10^-7 M. However, in the presence of acetic acid, the concentration of H+ ions will be slightly higher. Therefore, the pH at the equivalence point will be slightly acidic, but it will not be as low as the pH of a strong acid.

Conclusion:

The pH at the equivalence point of the titration between M/5 CH3COONa and M/5 HCl will be slightly acidic, but it will not be as low as the pH of a strong acid. This is because acetic acid, which is a weak acid, is formed during the reaction. The exact pH value will depend on the concentrations of the solutions and the dissociation constant of acetic acid (pKa value).

Answered by Infinity Academy · View profile

Attention JEE Students!

To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.

Physics for JEE Main & Advanced

Mock Tests for JEE Main and Advanced 2025

Chemistry for JEE Main & Advanced

Mathematics (Maths) for JEE Main & Advanced

View all answers Start learning for free

Explore Courses for JEE exam

Similar JEE Doubts

Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.100 ml of 0.1 M H3 P02 is titrated with 0.1 M NaOH. The volume of NaOH needed will be

View answer

Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.Which of the following solutions, when mixed with 100 ml of 0.05 M NaOH, will give a neutral solution?

View answer

Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.How many gram of phosphoric acid (H3PO4) would be required to neutralize 58 g of magnesium hydroxide?

View answer

Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seamctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine. Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates. Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water ( = 18 g).Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule. 0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.When 5.00 g of a metal is strongly heated, 9.44 g of its oxide is obtained. The equivalent mass of the metal is

View answer

Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.9.8 g of an acid on treatment with excess of an alkali forms salt along with 3.6 g of water. What is the equivalent mass of the acid?

View answer

Top Courses for JEEView all

Physics for JEE Main & Advanced

Mock Tests for JEE Main and Advanced 2025

Chemistry for JEE Main & Advanced

Mathematics (Maths) for JEE Main & Advanced

Chapter-wise Tests for JEE Main & Advanced

Top Courses for JEE

View all

10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)(A) 0.7 (B) 1 (C) 1.88 (D) 2.88?

Share with a Friend

Answer this doubt

Question Description
10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)(A) 0.7 (B) 1 (C) 1.88 (D) 2.88? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)(A) 0.7 (B) 1 (C) 1.88 (D) 2.88? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)(A) 0.7 (B) 1 (C) 1.88 (D) 2.88?.

Solutions for 10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)(A) 0.7 (B) 1 (C) 1.88 (D) 2.88? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of 10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)(A) 0.7 (B) 1 (C) 1.88 (D) 2.88? defined & explained in the simplest way possible. Besides giving the explanation of 10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)(A) 0.7 (B) 1 (C) 1.88 (D) 2.88?, a detailed solution for 10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)(A) 0.7 (B) 1 (C) 1.88 (D) 2.88? has been provided alongside types of 10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)(A) 0.7 (B) 1 (C) 1.88 (D) 2.88? theory, EduRev gives you an ample number of questions to practice 10 mL of M/5 CH3COONa solution is titrated with M/5 HCl solution. The pH value at the equivalence point is: (pKa(CH3COOH) = 4)(A) 0.7 (B) 1 (C) 1.88 (D) 2.88? tests, examples and also practice JEE tests.

Explore Courses for JEE exam