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A train started at 9 AM from a station A with a speed of 72 km/hr. Another train after two hours started from the station B towards A with a speed of 90 km/ph. The two trains are expected to cross each other at 1.30 PM. At 12 noon because of the signals both the trains reduced their speeds by the same quantity and they crossed each other at 4.30 PM. The speed of the train, after 12 noon, that started from the station A, is
  • a)
    54
  • b)
    36
  • c)
    18
  • d)
    40
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A train started at 9 AM from a station A with a speed of 72 km/hr. Ano...

AC in coverd in 2 hr by 1st train = 72 × 2 = 144 km
BC in coverd by both trains in (11 am to  1: 30pm = 2.5 hr) so speed will be added (opposite direction)
⇒ (72 + 90) × 2.5
⇒ 162 × 2.5 = 405 km
Distance covered after 12 noon = 405 - (72 + 90) = 243 km
Time taken in 243 km (12 pm to 4: 30 pm) = 4.5 hr
Let the reduction be 'y' km/h in each train
So, the speed of both train = 243/4.5 = 54 km
⇒ (72 - y) + (90 - y) = 54
⇒ 162 - 2y = 54
⇒ 2y = 108
⇒ y = 54 km
The speed of the train, after 12 noon, that started from the station A, = 72 - x = 72 - 54 = 18 km/h
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Most Upvoted Answer
A train started at 9 AM from a station A with a speed of 72 km/hr. Ano...

Explanation:

Initial situation:
- Train A started at 9 AM with a speed of 72 km/hr
- Train B started at 11 AM with a speed of 90 km/hr
- They are expected to cross each other at 1.30 PM

Reduced speed situation:
- At 12 noon, both trains reduced their speeds by the same quantity
- They crossed each other at 4.30 PM

Calculating the distance:
- Let the distance between A and B be D km
- The relative speed of the two trains when they crossed each other at 1.30 PM = 72 + 90 = 162 km/hr
- The time taken to cross each other at 1.30 PM = 4.5 hours (from 9 AM to 1.30 PM)
- So, D = 162 * 4.5 = 729 km

Calculating the speed of Train A after 12 noon:
- Let the reduced speed of both trains be x km/hr
- From 12 noon to 4.30 PM, the time taken = 4.5 hours
- Distance covered by Train A after 12 noon = (72 - x) * 4.5
- Distance covered by Train B after 12 noon = (90 - x) * 4.5
- As they crossed each other, the sum of the distances covered by both trains after 12 noon = 729 km
- Therefore, (72 - x) * 4.5 + (90 - x) * 4.5 = 729
- Solving the above equation, we get x = 18 km/hr

Therefore, the speed of the train that started from station A after 12 noon is 18 km/hr (Option C).
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A train started at 9 AM from a station A with a speed of 72 km/hr. Another train after two hours started from the station B towards A with a speed of 90 km/ph. The two trains are expected to cross each other at 1.30 PM. At 12 noon because of the signals both the trains reduced their speeds by the same quantity and they crossed each other at 4.30 PM. The speed of the train, after 12 noon, that started from the station A, isa)54b)36c)18d)40Correct answer is option 'C'. Can you explain this answer?
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