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A rectangular surface of sides 10 cm and 15 cm is placed inside a uniform electric field of 25 V/m, such that the surface makes an angle of 30 degree with the direction of electric field.Find the flux of the electric field through the rectangular surface?
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A rectangular surface of sides 10 cm and 15 cm is placed inside a unif...
Flux is integral of E.dA , as E is constant throughout the area of the rectangular it comes out of the integral and gives us E.(integral of dA) which is E.A where A is the total area vector of the surfacenow by using dot product formula we get EAcos30 .
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A rectangular surface of sides 10 cm and 15 cm is placed inside a unif...
§=E. dA Electric Flux will be in z direction. §=Q\A€;§=E COS30=0
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A rectangular surface of sides 10 cm and 15 cm is placed inside a unif...
Calculating Electric Flux through a Rectangular Surface
Electric flux through a surface is defined as the total number of electric field lines passing through that surface. In this case, we have a rectangular surface with sides 10 cm and 15 cm placed at an angle of 30 degrees to an electric field of 25 V/m.
Calculating the Area Vector
To calculate the electric flux through the surface, we first need to determine the area vector of the surface. The area vector is perpendicular to the surface and has a magnitude equal to the area of the surface. In this case, the area of the rectangular surface can be calculated as 10 cm x 15 cm = 150 cm².
Calculating the Component of Electric Field Normal to the Surface
Next, we need to calculate the component of the electric field that is normal to the surface. This can be done by multiplying the magnitude of the electric field by the cosine of the angle between the electric field and the normal to the surface. In this case, the component of the electric field normal to the surface is 25 V/m x cos(30°) = 21.65 V/m.
Calculating Electric Flux
Finally, we can calculate the electric flux through the surface by taking the dot product of the electric field and the area vector. The electric flux is given by the formula:
Electric Flux = Electric Field x Area x cos(θ)
Substituting the values we calculated:
Electric Flux = 21.65 V/m x 150 cm² x cos(30°) = 311.12 V·cm
Therefore, the electric flux through the rectangular surface is 311.12 V·cm.
Electric flux through a surface is defined as the total number of electric field lines passing through that surface. In this case, we have a rectangular surface with sides 10 cm and 15 cm placed at an angle of 30 degrees to an electric field of 25 V/m.
Calculating the Area Vector
To calculate the electric flux through the surface, we first need to determine the area vector of the surface. The area vector is perpendicular to the surface and has a magnitude equal to the area of the surface. In this case, the area of the rectangular surface can be calculated as 10 cm x 15 cm = 150 cm².
Calculating the Component of Electric Field Normal to the Surface
Next, we need to calculate the component of the electric field that is normal to the surface. This can be done by multiplying the magnitude of the electric field by the cosine of the angle between the electric field and the normal to the surface. In this case, the component of the electric field normal to the surface is 25 V/m x cos(30°) = 21.65 V/m.
Calculating Electric Flux
Finally, we can calculate the electric flux through the surface by taking the dot product of the electric field and the area vector. The electric flux is given by the formula:
Electric Flux = Electric Field x Area x cos(θ)
Substituting the values we calculated:
Electric Flux = 21.65 V/m x 150 cm² x cos(30°) = 311.12 V·cm
Therefore, the electric flux through the rectangular surface is 311.12 V·cm.
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A rectangular surface of sides 10 cm and 15 cm is placed inside a uniform electric field of 25 V/m, such that the surface makes an angle of 30 degree with the direction of electric field.Find the flux of the electric field through the rectangular surface?
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A rectangular surface of sides 10 cm and 15 cm is placed inside a uniform electric field of 25 V/m, such that the surface makes an angle of 30 degree with the direction of electric field.Find the flux of the electric field through the rectangular surface? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A rectangular surface of sides 10 cm and 15 cm is placed inside a uniform electric field of 25 V/m, such that the surface makes an angle of 30 degree with the direction of electric field.Find the flux of the electric field through the rectangular surface? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular surface of sides 10 cm and 15 cm is placed inside a uniform electric field of 25 V/m, such that the surface makes an angle of 30 degree with the direction of electric field.Find the flux of the electric field through the rectangular surface?.
A rectangular surface of sides 10 cm and 15 cm is placed inside a uniform electric field of 25 V/m, such that the surface makes an angle of 30 degree with the direction of electric field.Find the flux of the electric field through the rectangular surface? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A rectangular surface of sides 10 cm and 15 cm is placed inside a uniform electric field of 25 V/m, such that the surface makes an angle of 30 degree with the direction of electric field.Find the flux of the electric field through the rectangular surface? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular surface of sides 10 cm and 15 cm is placed inside a uniform electric field of 25 V/m, such that the surface makes an angle of 30 degree with the direction of electric field.Find the flux of the electric field through the rectangular surface?.
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