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Direction (Q. No. 16 and 17): Refer to the given passage and answer the following questions. A balloon is moving upwards from the R 2 m ground with a constant speed of 10 m-s¹, at a H-15 m distance of 5.m.in front (A) 2.2 s (C) 4.6 s 40.5 m *S -5m- of a plane mirror of length 2 m as shown in the given figure. A source S is placed symmetrically in front of the plane mirror. The plane mirror is placed at a height H = 15 m above the ground Ground .?
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Direction (Q. No. 16 and 17): Refer to the given passage and answer th...
Explanation


Given information:


  • The balloon is moving upwards from the ground with a constant speed of 10 m/s.

  • The balloon is at a distance of 5 m in front of a plane mirror.

  • The length of the plane mirror is 2 m.

  • A source S is placed symmetrically in front of the plane mirror.

  • The height of the plane mirror above the ground is 15 m.



Calculating the time taken by the balloon to reach the mirror:

To find the time taken by the balloon to reach the mirror, we can use the formula:

Time = Distance / Speed

The distance between the balloon and the mirror is 5 m, and the speed of the balloon is 10 m/s. Therefore, the time taken by the balloon to reach the mirror is:

Time = 5 m / 10 m/s = 0.5 s


Calculating the distance traveled by the balloon in the given time:

Since the balloon is moving upwards with a constant speed, the distance traveled by the balloon in 0.5 s is:

Distance = Speed × Time = 10 m/s × 0.5 s = 5 m


Calculating the total height of the balloon above the ground:

The balloon is initially at a height of 2 m above the ground. As it moves upwards, it travels a distance of 5 m in 0.5 s. Therefore, the total height of the balloon above the ground is:

Total Height = Initial Height + Distance Traveled = 2 m + 5 m = 7 m


Calculating the height of the source above the ground:

The height of the plane mirror above the ground is given as 15 m. Since the source is placed symmetrically in front of the mirror, the height of the source above the ground is half the height of the mirror:

Height of Source = Height of Mirror / 2 = 15 m / 2 = 7.5 m


Conclusion:

The balloon reaches the plane mirror in 0.5 seconds. At that time, the total height of the balloon above the ground is 7 meters, and the height of the source above the ground is 7.5 meters.
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Direction (Q. No. 16 and 17): Refer to the given passage and answer the following questions. A balloon is moving upwards from the R 2 m ground with a constant speed of 10 m-s¹, at a H-15 m distance of 5.m.in front (A) 2.2 s (C) 4.6 s 40.5 m *S -5m- of a plane mirror of length 2 m as shown in the given figure. A source S is placed symmetrically in front of the plane mirror. The plane mirror is placed at a height H = 15 m above the ground Ground .?
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Direction (Q. No. 16 and 17): Refer to the given passage and answer the following questions. A balloon is moving upwards from the R 2 m ground with a constant speed of 10 m-s¹, at a H-15 m distance of 5.m.in front (A) 2.2 s (C) 4.6 s 40.5 m *S -5m- of a plane mirror of length 2 m as shown in the given figure. A source S is placed symmetrically in front of the plane mirror. The plane mirror is placed at a height H = 15 m above the ground Ground .? for Class 8 2024 is part of Class 8 preparation. The Question and answers have been prepared according to the Class 8 exam syllabus. Information about Direction (Q. No. 16 and 17): Refer to the given passage and answer the following questions. A balloon is moving upwards from the R 2 m ground with a constant speed of 10 m-s¹, at a H-15 m distance of 5.m.in front (A) 2.2 s (C) 4.6 s 40.5 m *S -5m- of a plane mirror of length 2 m as shown in the given figure. A source S is placed symmetrically in front of the plane mirror. The plane mirror is placed at a height H = 15 m above the ground Ground .? covers all topics & solutions for Class 8 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. No. 16 and 17): Refer to the given passage and answer the following questions. A balloon is moving upwards from the R 2 m ground with a constant speed of 10 m-s¹, at a H-15 m distance of 5.m.in front (A) 2.2 s (C) 4.6 s 40.5 m *S -5m- of a plane mirror of length 2 m as shown in the given figure. A source S is placed symmetrically in front of the plane mirror. The plane mirror is placed at a height H = 15 m above the ground Ground .?.
Solutions for Direction (Q. No. 16 and 17): Refer to the given passage and answer the following questions. A balloon is moving upwards from the R 2 m ground with a constant speed of 10 m-s¹, at a H-15 m distance of 5.m.in front (A) 2.2 s (C) 4.6 s 40.5 m *S -5m- of a plane mirror of length 2 m as shown in the given figure. A source S is placed symmetrically in front of the plane mirror. The plane mirror is placed at a height H = 15 m above the ground Ground .? in English & in Hindi are available as part of our courses for Class 8. Download more important topics, notes, lectures and mock test series for Class 8 Exam by signing up for free.
Here you can find the meaning of Direction (Q. No. 16 and 17): Refer to the given passage and answer the following questions. A balloon is moving upwards from the R 2 m ground with a constant speed of 10 m-s¹, at a H-15 m distance of 5.m.in front (A) 2.2 s (C) 4.6 s 40.5 m *S -5m- of a plane mirror of length 2 m as shown in the given figure. A source S is placed symmetrically in front of the plane mirror. The plane mirror is placed at a height H = 15 m above the ground Ground .? defined & explained in the simplest way possible. Besides giving the explanation of Direction (Q. No. 16 and 17): Refer to the given passage and answer the following questions. A balloon is moving upwards from the R 2 m ground with a constant speed of 10 m-s¹, at a H-15 m distance of 5.m.in front (A) 2.2 s (C) 4.6 s 40.5 m *S -5m- of a plane mirror of length 2 m as shown in the given figure. A source S is placed symmetrically in front of the plane mirror. The plane mirror is placed at a height H = 15 m above the ground Ground .?, a detailed solution for Direction (Q. No. 16 and 17): Refer to the given passage and answer the following questions. A balloon is moving upwards from the R 2 m ground with a constant speed of 10 m-s¹, at a H-15 m distance of 5.m.in front (A) 2.2 s (C) 4.6 s 40.5 m *S -5m- of a plane mirror of length 2 m as shown in the given figure. A source S is placed symmetrically in front of the plane mirror. The plane mirror is placed at a height H = 15 m above the ground Ground .? has been provided alongside types of Direction (Q. No. 16 and 17): Refer to the given passage and answer the following questions. A balloon is moving upwards from the R 2 m ground with a constant speed of 10 m-s¹, at a H-15 m distance of 5.m.in front (A) 2.2 s (C) 4.6 s 40.5 m *S -5m- of a plane mirror of length 2 m as shown in the given figure. A source S is placed symmetrically in front of the plane mirror. The plane mirror is placed at a height H = 15 m above the ground Ground .? theory, EduRev gives you an ample number of questions to practice Direction (Q. No. 16 and 17): Refer to the given passage and answer the following questions. A balloon is moving upwards from the R 2 m ground with a constant speed of 10 m-s¹, at a H-15 m distance of 5.m.in front (A) 2.2 s (C) 4.6 s 40.5 m *S -5m- of a plane mirror of length 2 m as shown in the given figure. A source S is placed symmetrically in front of the plane mirror. The plane mirror is placed at a height H = 15 m above the ground Ground .? tests, examples and also practice Class 8 tests.
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