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An organ pipe 40 cm long is open at both ends. The speed of sound in air is 360 ms-1.The frequency of the second harmonic is ___________ Hz.
Correct answer is '900'. Can you explain this answer?
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An organ pipe 40 cmlong is open at both ends. The speed of sound in ai...
Given:
Length of the organ pipe (L) = 40 cm = 0.4 m
Speed of sound in air (v) = 360 m/s
To find:
Frequency of the second harmonic
Formula:
The frequency of the nth harmonic in an open pipe is given by the equation:
fn = (nv) / (2L)
where:
fn = frequency of the nth harmonic
n = harmonic number
v = speed of sound
L = length of the pipe
Calculation:
We are given that the pipe is open at both ends, which means it supports odd harmonics only (1st, 3rd, 5th, etc.). The second harmonic is the first odd harmonic.
Using the formula, we can calculate the frequency of the second harmonic as follows:
f2 = (2v) / (2L)
f2 = v / L
Substituting the given values:
f2 = 360 m/s / 0.4 m
f2 = 900 Hz
Therefore, the frequency of the second harmonic is 900 Hz.
Length of the organ pipe (L) = 40 cm = 0.4 m
Speed of sound in air (v) = 360 m/s
To find:
Frequency of the second harmonic
Formula:
The frequency of the nth harmonic in an open pipe is given by the equation:
fn = (nv) / (2L)
where:
fn = frequency of the nth harmonic
n = harmonic number
v = speed of sound
L = length of the pipe
Calculation:
We are given that the pipe is open at both ends, which means it supports odd harmonics only (1st, 3rd, 5th, etc.). The second harmonic is the first odd harmonic.
Using the formula, we can calculate the frequency of the second harmonic as follows:
f2 = (2v) / (2L)
f2 = v / L
Substituting the given values:
f2 = 360 m/s / 0.4 m
f2 = 900 Hz
Therefore, the frequency of the second harmonic is 900 Hz.
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Community Answer
An organ pipe 40 cmlong is open at both ends. The speed of sound in ai...
An organ pipe that is open at both ends resonates at all harmonics, including the fundamental (first harmonic), second harmonic, third harmonic, etc.
The frequency f of the n-th harmonic for a pipe open at both ends is given by:
where:
n is the number of the harmonic,
v is the speed of sound, and
L is the length of the pipe.
n is the number of the harmonic,
v is the speed of sound, and
L is the length of the pipe.
To find the frequency of the second harmonic (n = 2) we can substitute the given values into the formula:
Therefore, the frequency of the second harmonic is 900 Hz.
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An organ pipe 40 cmlong is open at both ends. The speed of sound in air is 360 ms-1.The frequency of the second harmonic is ___________ Hz.Correct answer is '900'. Can you explain this answer?
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An organ pipe 40 cmlong is open at both ends. The speed of sound in air is 360 ms-1.The frequency of the second harmonic is ___________ Hz.Correct answer is '900'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An organ pipe 40 cmlong is open at both ends. The speed of sound in air is 360 ms-1.The frequency of the second harmonic is ___________ Hz.Correct answer is '900'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organ pipe 40 cmlong is open at both ends. The speed of sound in air is 360 ms-1.The frequency of the second harmonic is ___________ Hz.Correct answer is '900'. Can you explain this answer?.
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