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Find the value of ‘k’ if the polynomials 2x³ + kx² + 3x - 5 and x³ + x² - 4x -k leave the same remainder when divided by (x-1)?
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Find the value of ‘k’ if the polynomials 2x³ + kx² + 3x - 5 and x³ + x...
Introduction:
To find the value of 'k' such that the polynomials 2x³ + kx² + 3x - 5 and x³ + x² - 4x - k leave the same remainder when divided by (x-1), we will use the Remainder Theorem.

Remainder Theorem:
The Remainder Theorem states that if a polynomial f(x) is divided by (x-a), the remainder is equal to f(a).

Step 1: Divide the polynomials by (x-1):
We will divide the polynomials 2x³ + kx² + 3x - 5 and x³ + x² - 4x - k by (x-1) using long division.


2x² + (k+2)x + (k+3)
____________________________
x - 1 | 2x³ + kx² + 3x - 5
2x³ - 2x²
___________
(k+2)x² + 3x
(k+2)x² - (k+2)x
_________________
4x - 5
4x - 4
__________
-1


The remainder is -1.


x² - 3x + (k-1)
______________________
x - 1 | x³ + x² - 4x - k
x³ - x²
___________
2x² - 4x
2x² - 2x
__________
-2x - k
-2x + 2
__________
-k - 2


The remainder is -k - 2.

Step 2: Equate the remainders:
Since the two polynomials leave the same remainder when divided by (x-1), we equate the remainders obtained.

-1 = -k - 2

Step 3: Solve for 'k':
To solve for 'k', we will isolate the variable on one side of the equation.

-1 + 2 = -k

1 = -k

k = -1

Conclusion:
The value of 'k' that makes the polynomials 2x³ + kx² + 3x - 5 and x³ + x² - 4x - k leave the same remainder when divided by (x-1) is k = -1.
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