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The leakage current of a transistor with usual notation are ICEO = 410 μA, ICBO = 5 μA, and IB = 30μA. Calculate the IC ________mA. (Correct up to two decimal places)
  • a)
    7.84
  • b)
    8.96
  • c)
    1.02
  • d)
    2.84
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The leakage current of a transistor with usual notation are ICEO= 410 ...
Given,
ICEO = 410 μA
ICBO = 5 μA
IB = 30μA
The collector current IC for CE circuit is,
IC = βIB + ICBO(β + 1)
In the case of leakage current, the value of base current is very small in comparison to the collector current (IC). So, the base current (IB) is negelected.

Again, from equation (i), we get
IC = 81 x 30 + 82 x 5
IC = 2.84 mA
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The leakage current of a transistor with usual notation are ICEO= 410 μA, ICBO= 5 μA, and IB= 30μA. Calculate the IC________mA. (Correct up to two decimal places)a)7.84b)8.96c)1.02d)2.84Correct answer is option 'D'. Can you explain this answer?
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