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A coil has an inductance of 2H and resistance of 4Ω. A 10V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ___________ × 10−2 J.
Correct answer is '625'. Can you explain this answer?
Verified Answer
A coil has an inductance of 2H and resistance of 4Ω. A 10V is ap...
To find the energy stored in the magnetic field after the current has built up to its equilibrium value, we first need to find the steady-state current in the coil.
When the current reaches its equilibrium value, the coil behaves like a resistor because the back-emf induced by the changing magnetic field is zero. Ohm's law can be applied:
I = V/R
where
I is the current
V is the voltage across the coil (10 V)
R is the resistance of the coil (4 Ω)
I is the current
V is the voltage across the coil (10 V)
R is the resistance of the coil (4 Ω)
Plugging in the values:
Now that we have the steady-state current, we can find the energy stored in the magnetic field using the formula:
Now that we have the steady-state current, we can find the energy stored in the magnetic field using the formula:
where
W is the energy stored in the magnetic field
L is the inductance of the coil (2 H)
I is the steady-state current (2.5 A)
W is the energy stored in the magnetic field
L is the inductance of the coil (2 H)
I is the steady-state current (2.5 A)
Plugging in the values:
To express this in terms of 10−2 J, divide by 10−2:
6.25 ÷ 10−2 = 625
Therefore, the energy stored in the magnetic field after the current has built up to its equilibrium value is 625 × 10−2 J.
To express this in terms of 10−2 J, divide by 10−2:
6.25 ÷ 10−2 = 625
Therefore, the energy stored in the magnetic field after the current has built up to its equilibrium value is 625 × 10−2 J.
Most Upvoted Answer
A coil has an inductance of 2H and resistance of 4Ω. A 10V is ap...
To find the impedance of the coil, we will use the formula Z = √(R^2 + (XL - XC)^2), where R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance.
Given:
Inductance (L) = 2H
Resistance (R) = 4Ω
The inductive reactance (XL) can be calculated using the formula XL = 2πfL, where f is the frequency and L is the inductance.
Assuming the frequency is not given, we cannot calculate the inductive reactance accurately. The inductive reactance depends on the frequency of the alternating current passing through the coil.
Similarly, the capacitive reactance (XC) cannot be determined without knowing the frequency and the capacitance.
Therefore, we cannot calculate the impedance of the coil without additional information.
Given:
Inductance (L) = 2H
Resistance (R) = 4Ω
The inductive reactance (XL) can be calculated using the formula XL = 2πfL, where f is the frequency and L is the inductance.
Assuming the frequency is not given, we cannot calculate the inductive reactance accurately. The inductive reactance depends on the frequency of the alternating current passing through the coil.
Similarly, the capacitive reactance (XC) cannot be determined without knowing the frequency and the capacitance.
Therefore, we cannot calculate the impedance of the coil without additional information.
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A coil has an inductance of 2H and resistance of 4Ω. A 10V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ___________ × 10−2 J.Correct answer is '625'. Can you explain this answer?
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A coil has an inductance of 2H and resistance of 4Ω. A 10V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ___________ × 10−2 J.Correct answer is '625'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A coil has an inductance of 2H and resistance of 4Ω. A 10V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ___________ × 10−2 J.Correct answer is '625'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A coil has an inductance of 2H and resistance of 4Ω. A 10V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ___________ × 10−2 J.Correct answer is '625'. Can you explain this answer?.
A coil has an inductance of 2H and resistance of 4Ω. A 10V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ___________ × 10−2 J.Correct answer is '625'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A coil has an inductance of 2H and resistance of 4Ω. A 10V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ___________ × 10−2 J.Correct answer is '625'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A coil has an inductance of 2H and resistance of 4Ω. A 10V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ___________ × 10−2 J.Correct answer is '625'. Can you explain this answer?.
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A coil has an inductance of 2H and resistance of 4Ω. A 10V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ___________ × 10−2 J.Correct answer is '625'. Can you explain this answer?, a detailed solution for A coil has an inductance of 2H and resistance of 4Ω. A 10V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ___________ × 10−2 J.Correct answer is '625'. Can you explain this answer? has been provided alongside types of A coil has an inductance of 2H and resistance of 4Ω. A 10V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be ___________ × 10−2 J.Correct answer is '625'. Can you explain this answer? theory, EduRev gives you an
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