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A bag contains 20 coins each labeled with one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down and the coin it kept back in the bag before the next draw. If the process is continued for five times, then what is the probability that the letters on the drawn coins make the word ‘DRAWN’, in that sequence?
Please anyone solve this question?
Please anyone solve this question?
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A bag contains 20 coins each labeled with one-letter code for amino ac...
Problem Statement:
A bag contains 20 coins, each labeled with a one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down, and the coin is put back into the bag before the next draw. If the process is continued for five times, what is the probability that the letters on the drawn coins make the word 'DRAWN', in that sequence?
Solution:
To find the probability of drawing the letters in the sequence 'DRAWN', we need to consider the number of favorable outcomes and the total number of possible outcomes.
Total Number of Possible Outcomes:
Since each coin can be drawn with replacement, there are 20 possibilities for each draw. As we are drawing 5 coins, the total number of possible outcomes is 20^5.
Total Number of Possible Outcomes = 20^5
Favorable Outcomes:
To form the word 'DRAWN' in the given sequence, we need to consider the following conditions for each letter:
1. 'D' can only be drawn as the first letter.
2. 'R' can be drawn as the second letter, following 'D'.
3. 'A' can be drawn as the third letter, following 'R'.
4. 'W' can be drawn as the fourth letter, following 'A'.
5. 'N' can be drawn as the fifth letter, following 'W'.
Favorable Outcomes for 'D':
Since 'D' can only be drawn as the first letter, there is only 1 possible outcome.
Favorable Outcomes for 'D' = 1
Favorable Outcomes for 'R':
After drawing 'D' as the first letter, there are still 20 possibilities for each draw. Therefore, the number of favorable outcomes for 'R' is 20.
Favorable Outcomes for 'R' = 20
Favorable Outcomes for 'A':
After drawing 'R' as the second letter, there are again 20 possibilities for each draw. Therefore, the number of favorable outcomes for 'A' is 20.
Favorable Outcomes for 'A' = 20
Favorable Outcomes for 'W':
After drawing 'A' as the third letter, there are 20 possibilities for each draw. Therefore, the number of favorable outcomes for 'W' is 20.
Favorable Outcomes for 'W' = 20
Favorable Outcomes for 'N':
After drawing 'W' as the fourth letter, there are 20 possibilities for each draw. Therefore, the number of favorable outcomes for 'N' is 20.
Favorable Outcomes for 'N' = 20
Total Number of Favorable Outcomes:
To find the total number of favorable outcomes, we need to multiply the favorable outcomes for each letter.
Total Number of Favorable Outcomes = Favorable Outcomes for 'D' * Favorable Outcomes for 'R' * Favorable Outcomes for 'A' * Favorable Outcomes for 'W' * Favorable Outcomes for 'N'
Total Number of Favorable Outcomes = 1 * 20 * 20 * 20 * 20
Total Number of Favorable Out
A bag contains 20 coins, each labeled with a one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down, and the coin is put back into the bag before the next draw. If the process is continued for five times, what is the probability that the letters on the drawn coins make the word 'DRAWN', in that sequence?
Solution:
To find the probability of drawing the letters in the sequence 'DRAWN', we need to consider the number of favorable outcomes and the total number of possible outcomes.
Total Number of Possible Outcomes:
Since each coin can be drawn with replacement, there are 20 possibilities for each draw. As we are drawing 5 coins, the total number of possible outcomes is 20^5.
Total Number of Possible Outcomes = 20^5
Favorable Outcomes:
To form the word 'DRAWN' in the given sequence, we need to consider the following conditions for each letter:
1. 'D' can only be drawn as the first letter.
2. 'R' can be drawn as the second letter, following 'D'.
3. 'A' can be drawn as the third letter, following 'R'.
4. 'W' can be drawn as the fourth letter, following 'A'.
5. 'N' can be drawn as the fifth letter, following 'W'.
Favorable Outcomes for 'D':
Since 'D' can only be drawn as the first letter, there is only 1 possible outcome.
Favorable Outcomes for 'D' = 1
Favorable Outcomes for 'R':
After drawing 'D' as the first letter, there are still 20 possibilities for each draw. Therefore, the number of favorable outcomes for 'R' is 20.
Favorable Outcomes for 'R' = 20
Favorable Outcomes for 'A':
After drawing 'R' as the second letter, there are again 20 possibilities for each draw. Therefore, the number of favorable outcomes for 'A' is 20.
Favorable Outcomes for 'A' = 20
Favorable Outcomes for 'W':
After drawing 'A' as the third letter, there are 20 possibilities for each draw. Therefore, the number of favorable outcomes for 'W' is 20.
Favorable Outcomes for 'W' = 20
Favorable Outcomes for 'N':
After drawing 'W' as the fourth letter, there are 20 possibilities for each draw. Therefore, the number of favorable outcomes for 'N' is 20.
Favorable Outcomes for 'N' = 20
Total Number of Favorable Outcomes:
To find the total number of favorable outcomes, we need to multiply the favorable outcomes for each letter.
Total Number of Favorable Outcomes = Favorable Outcomes for 'D' * Favorable Outcomes for 'R' * Favorable Outcomes for 'A' * Favorable Outcomes for 'W' * Favorable Outcomes for 'N'
Total Number of Favorable Outcomes = 1 * 20 * 20 * 20 * 20
Total Number of Favorable Out
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A bag contains 20 coins each labeled with one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down and the coin it kept back in the bag before the next draw. If the process is continued for five times, then what is the probability that the letters on the drawn coins make the word ‘DRAWN’, in that sequence? Please anyone solve this question?
Question Description
A bag contains 20 coins each labeled with one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down and the coin it kept back in the bag before the next draw. If the process is continued for five times, then what is the probability that the letters on the drawn coins make the word ‘DRAWN’, in that sequence? Please anyone solve this question? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A bag contains 20 coins each labeled with one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down and the coin it kept back in the bag before the next draw. If the process is continued for five times, then what is the probability that the letters on the drawn coins make the word ‘DRAWN’, in that sequence? Please anyone solve this question? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bag contains 20 coins each labeled with one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down and the coin it kept back in the bag before the next draw. If the process is continued for five times, then what is the probability that the letters on the drawn coins make the word ‘DRAWN’, in that sequence? Please anyone solve this question?.
A bag contains 20 coins each labeled with one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down and the coin it kept back in the bag before the next draw. If the process is continued for five times, then what is the probability that the letters on the drawn coins make the word ‘DRAWN’, in that sequence? Please anyone solve this question? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A bag contains 20 coins each labeled with one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down and the coin it kept back in the bag before the next draw. If the process is continued for five times, then what is the probability that the letters on the drawn coins make the word ‘DRAWN’, in that sequence? Please anyone solve this question? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bag contains 20 coins each labeled with one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down and the coin it kept back in the bag before the next draw. If the process is continued for five times, then what is the probability that the letters on the drawn coins make the word ‘DRAWN’, in that sequence? Please anyone solve this question?.
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A bag contains 20 coins each labeled with one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down and the coin it kept back in the bag before the next draw. If the process is continued for five times, then what is the probability that the letters on the drawn coins make the word ‘DRAWN’, in that sequence? Please anyone solve this question?, a detailed solution for A bag contains 20 coins each labeled with one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down and the coin it kept back in the bag before the next draw. If the process is continued for five times, then what is the probability that the letters on the drawn coins make the word ‘DRAWN’, in that sequence? Please anyone solve this question? has been provided alongside types of A bag contains 20 coins each labeled with one-letter code for amino acids. A coin is drawn at random, the letter on the coin is noted down and the coin it kept back in the bag before the next draw. If the process is continued for five times, then what is the probability that the letters on the drawn coins make the word ‘DRAWN’, in that sequence? Please anyone solve this question? theory, EduRev gives you an
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