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At 90° C, the vapour pressure of toluene is 400 Torr and that of o-xylene is 150 Torr. What is the composition of the liquid mixture that boils at 90°C when the pressure is 0.50 atm? What is the composition of the vapour produced?
- a)48.4 mol% Toluene
- b)96.8 mol% Toluene
- c)193.2 mol% Toluene
- d)24.2 mol% Toluene
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
At 90° C, the vapour pressure of toluene is 400 Torr and that of o...
Given Data:
- Vapour pressure of toluene at 90°C = 400 Torr
- Vapour pressure of o-xylene at 90°C = 150 Torr
- Total pressure of the system = 0.50 atm
Calculating the Composition of the Liquid Mixture:
- Let x be the mole fraction of toluene in the liquid mixture.
- According to Raoult's law, the partial pressure of toluene (Pt) and o-xylene (Po) in the liquid mixture can be calculated using the following equations:
Pt = x * P°t
Po = (1 - x) * P°o
- Given that Pt + Po = 0.50 atm, we can substitute the values of Pt and Po from the equations above and solve for x.
- By solving the equations, we find that x = 0.968 or 96.8%. Therefore, the composition of the liquid mixture is 96.8 mol% toluene.
Calculating the Composition of the Vapour:
- The mole fraction of toluene in the vapour phase can be calculated using Dalton's law of partial pressures.
- According to Dalton's law, the mole fraction of toluene in the vapour phase (yt) is given by:
yt = Pt / Ptotal
- Substituting the values of Pt and Ptotal, we find yt = 0.968 or 96.8%. Therefore, the composition of the vapour produced is 96.8 mol% toluene.
Therefore, the correct answer is option B - 96.8 mol% Toluene.
- Vapour pressure of toluene at 90°C = 400 Torr
- Vapour pressure of o-xylene at 90°C = 150 Torr
- Total pressure of the system = 0.50 atm
Calculating the Composition of the Liquid Mixture:
- Let x be the mole fraction of toluene in the liquid mixture.
- According to Raoult's law, the partial pressure of toluene (Pt) and o-xylene (Po) in the liquid mixture can be calculated using the following equations:
Pt = x * P°t
Po = (1 - x) * P°o
- Given that Pt + Po = 0.50 atm, we can substitute the values of Pt and Po from the equations above and solve for x.
- By solving the equations, we find that x = 0.968 or 96.8%. Therefore, the composition of the liquid mixture is 96.8 mol% toluene.
Calculating the Composition of the Vapour:
- The mole fraction of toluene in the vapour phase can be calculated using Dalton's law of partial pressures.
- According to Dalton's law, the mole fraction of toluene in the vapour phase (yt) is given by:
yt = Pt / Ptotal
- Substituting the values of Pt and Ptotal, we find yt = 0.968 or 96.8%. Therefore, the composition of the vapour produced is 96.8 mol% toluene.
Therefore, the correct answer is option B - 96.8 mol% Toluene.
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Community Answer
At 90° C, the vapour pressure of toluene is 400 Torr and that of o...
Toluene and o-xylene both are volatile liquids and the mixture boils at 90°C when total pressure is 0.50 atm (= 380 Torr)
Let mole fraction of toluene in the mixture be = XT
Its vapour pressure in mixture PT = P0T XT=400 XT
and vapour pressure of o-xylene P0 = 150(1 –XT)
400XT + 150(1 –XT) = 380
XT = 0.92
Hence, mixture contains 92 mol% toluene
Mole fraction of toluene in vapour
Hence, mixture contains 96.8 mol% toluene in vapour.
Let mole fraction of toluene in the mixture be = XT
Its vapour pressure in mixture PT = P0T XT=400 XT
and vapour pressure of o-xylene P0 = 150(1 –XT)
400XT + 150(1 –XT) = 380
XT = 0.92
Hence, mixture contains 92 mol% toluene
Mole fraction of toluene in vapour
Hence, mixture contains 96.8 mol% toluene in vapour.
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At 90° C, the vapour pressure of toluene is 400 Torr and that of o-xylene is 150 Torr. What is the composition of the liquid mixture that boils at 90°C when the pressure is 0.50 atm? What is the composition of the vapour produced?a)48.4 mol% Tolueneb)96.8 mol% Toluenec)193.2 mol% Toluened)24.2 mol% TolueneCorrect answer is option 'B'. Can you explain this answer?
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At 90° C, the vapour pressure of toluene is 400 Torr and that of o-xylene is 150 Torr. What is the composition of the liquid mixture that boils at 90°C when the pressure is 0.50 atm? What is the composition of the vapour produced?a)48.4 mol% Tolueneb)96.8 mol% Toluenec)193.2 mol% Toluened)24.2 mol% TolueneCorrect answer is option 'B'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about At 90° C, the vapour pressure of toluene is 400 Torr and that of o-xylene is 150 Torr. What is the composition of the liquid mixture that boils at 90°C when the pressure is 0.50 atm? What is the composition of the vapour produced?a)48.4 mol% Tolueneb)96.8 mol% Toluenec)193.2 mol% Toluened)24.2 mol% TolueneCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 90° C, the vapour pressure of toluene is 400 Torr and that of o-xylene is 150 Torr. What is the composition of the liquid mixture that boils at 90°C when the pressure is 0.50 atm? What is the composition of the vapour produced?a)48.4 mol% Tolueneb)96.8 mol% Toluenec)193.2 mol% Toluened)24.2 mol% TolueneCorrect answer is option 'B'. Can you explain this answer?.
At 90° C, the vapour pressure of toluene is 400 Torr and that of o-xylene is 150 Torr. What is the composition of the liquid mixture that boils at 90°C when the pressure is 0.50 atm? What is the composition of the vapour produced?a)48.4 mol% Tolueneb)96.8 mol% Toluenec)193.2 mol% Toluened)24.2 mol% TolueneCorrect answer is option 'B'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about At 90° C, the vapour pressure of toluene is 400 Torr and that of o-xylene is 150 Torr. What is the composition of the liquid mixture that boils at 90°C when the pressure is 0.50 atm? What is the composition of the vapour produced?a)48.4 mol% Tolueneb)96.8 mol% Toluenec)193.2 mol% Toluened)24.2 mol% TolueneCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 90° C, the vapour pressure of toluene is 400 Torr and that of o-xylene is 150 Torr. What is the composition of the liquid mixture that boils at 90°C when the pressure is 0.50 atm? What is the composition of the vapour produced?a)48.4 mol% Tolueneb)96.8 mol% Toluenec)193.2 mol% Toluened)24.2 mol% TolueneCorrect answer is option 'B'. Can you explain this answer?.
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