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The major organic compound formed by the reaction of 1,1,1-trichloroethane with silver powder is:
- a)2-Butyne
- b)2-Butene
- c)Acetylene
- d)Ethene
Correct answer is option 'A'. Can you explain this answer?
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Introduction
The reaction of 1,1,1-trichloroethane with silver powder is a significant transformation in organic chemistry, leading to the formation of a major organic compound.
Reaction Overview
- 1,1,1-Trichloroethane (C2HCl3) is a halogenated hydrocarbon.
- Silver Powder (Ag) acts as a reducing agent.
Mechanism of Reaction
- The presence of silver powder facilitates the elimination of chlorine atoms from 1,1,1-trichloroethane.
- The reaction proceeds through a dehydrohalogenation mechanism where chlorine atoms are removed, resulting in the formation of a carbon-carbon triple bond.
Formation of 2-Butyne
- As chlorine atoms are eliminated, the structure rearranges to form a more stable alkyne.
- The major product from this reaction is 2-butyne (C4H6), which is an alkyne characterized by a triple bond between the second and third carbon atoms in the chain.
Comparison with Other Options
- 2-Butene (b): This is formed through hydrogenation but is not the major product in this reaction.
- Acetylene (c): This would require complete dehydrohalogenation, which is less favorable in this case.
- Ethene (d): This is a possible product but not the primary one due to the presence of multiple chlorine atoms promoting alkyne formation.
Conclusion
In summary, the reaction of 1,1,1-trichloroethane with silver powder primarily yields 2-butyne, showcasing the ability of silver as a reducing agent in facilitating the formation of carbon-carbon multiple bonds.
The reaction of 1,1,1-trichloroethane with silver powder is a significant transformation in organic chemistry, leading to the formation of a major organic compound.
Reaction Overview
- 1,1,1-Trichloroethane (C2HCl3) is a halogenated hydrocarbon.
- Silver Powder (Ag) acts as a reducing agent.
Mechanism of Reaction
- The presence of silver powder facilitates the elimination of chlorine atoms from 1,1,1-trichloroethane.
- The reaction proceeds through a dehydrohalogenation mechanism where chlorine atoms are removed, resulting in the formation of a carbon-carbon triple bond.
Formation of 2-Butyne
- As chlorine atoms are eliminated, the structure rearranges to form a more stable alkyne.
- The major product from this reaction is 2-butyne (C4H6), which is an alkyne characterized by a triple bond between the second and third carbon atoms in the chain.
Comparison with Other Options
- 2-Butene (b): This is formed through hydrogenation but is not the major product in this reaction.
- Acetylene (c): This would require complete dehydrohalogenation, which is less favorable in this case.
- Ethene (d): This is a possible product but not the primary one due to the presence of multiple chlorine atoms promoting alkyne formation.
Conclusion
In summary, the reaction of 1,1,1-trichloroethane with silver powder primarily yields 2-butyne, showcasing the ability of silver as a reducing agent in facilitating the formation of carbon-carbon multiple bonds.
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The major organic compound formed by the reaction of 1,1,1-trichloroethane with silver powder is:a)2-Butyneb)2-Butenec)Acetylened)EtheneCorrect answer is option 'A'. Can you explain this answer?
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