Conversion of Propene to 1-Propanol

To convert propene (CH3-CH=CH2) to 1-propanol (CH3-CH2-CH2OH), we need to perform an oxidation reaction. Among the given options, the ideal set of reagents to effect this conversion is option 'B' - BH3 and alkaline H2O2.

Explanation:

BH3 (Borane)
Borane (BH3) is a Lewis acid that can act as a reducing agent. It reacts with the carbon-carbon double bond (C=C) in propene to form a trialkylborane intermediate.

Alkaline H2O2 (Hydrogen Peroxide)
Alkaline hydrogen peroxide (H2O2) acts as an oxidizing agent. It oxidizes the trialkylborane intermediate formed in the previous step to form the corresponding alcohol.

Step-by-Step Reaction:

1. The reaction begins with the addition of BH3 to the carbon-carbon double bond (C=C) in propene. The BH3 molecule donates a pair of electrons to one carbon atom of the double bond, resulting in the formation of a trialkylborane intermediate.

2. In the next step, the trialkylborane intermediate reacts with alkaline hydrogen peroxide (H2O2). The H2O2 molecule donates an oxygen atom to the boron atom in the intermediate, resulting in the oxidation of boron from a lower oxidation state to a higher oxidation state.

3. Simultaneously, the oxygen atom that is donated to the boron atom forms a bond with the carbon atom adjacent to the boron atom. This forms a new carbon-oxygen (C-O) bond, resulting in the formation of 1-propanol.

Overall Reaction:

The overall reaction can be summarized as follows:

CH3-CH=CH2 + BH3 → CH3-CH(BH2)-CH3 (Trialkylborane intermediate)
CH3-CH(BH2)-CH3 + H2O2 → CH3-CH2-CH2OH (1-Propanol)

Therefore, the ideal set of reagents among the given options to convert propene to 1-propanol is BH3 and alkaline H2O2 (option 'B'). This combination allows for the oxidation of propene to 1-propanol through a two-step process involving the formation of a trialkylborane intermediate followed by its oxidation using alkaline hydrogen peroxide.