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The element molybdenum (Mo) combines with sulphur (S) to form a compound commonly called molybdenum disulphide which used in specialized lithium batteries. A sample of this compound contains 1.50 g of Mo for each 1.00 g of S. If a different sample of the compound contains 2.50 g of S, how many grams of Mo does it contain?
- a)2.00 g of Mo
- b)1.75 g of Mo
- c)3.75 g of Mo
- d)5.75 g of Mo
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The element molybdenum (Mo) combines with sulphur (S) to form a compou...
The first sample has a Mo to S mass ratio is: 
In the second sample, we know the mass of S (2.50 g) and the mass of Mo is unknown. The mass ratio of Mo to S in the second sample is, therefore,
Now we equate them, because the two ratios must be equal according to law of definite proportions.
On Solving, the mass of Mo is
In the second sample, we know the mass of S (2.50 g) and the mass of Mo is unknown. The mass ratio of Mo to S in the second sample is, therefore,
Now we equate them, because the two ratios must be equal according to law of definite proportions.
On Solving, the mass of Mo is
Most Upvoted Answer
The element molybdenum (Mo) combines with sulphur (S) to form a compou...
To determine the amount of molybdenum (Mo) in a sample of molybdenum disulphide (MoS2) that contains 2.50 g of sulphur (S), we can use the given ratio of Mo to S in the compound.
Given:
1.50 g of Mo for each 1.00 g of S
Let's assume the mass of Mo in the sample is 'x' grams.
- Identify the given information:
- Mass of sulphur (S): 2.50 g
- Set up a proportion using the given ratio:
- (1.50 g Mo) / (1.00 g S) = x g Mo / (2.50 g S)
- Solve the proportion for 'x':
- (1.50 g)(2.50 g) = (1.00 g)(x g)
- 3.75 g = x g
Therefore, the sample contains 3.75 g of molybdenum (Mo). Hence, option 'C' (3.75 g of Mo) is the correct answer.
Given:
1.50 g of Mo for each 1.00 g of S
Let's assume the mass of Mo in the sample is 'x' grams.
- Identify the given information:
- Mass of sulphur (S): 2.50 g
- Set up a proportion using the given ratio:
- (1.50 g Mo) / (1.00 g S) = x g Mo / (2.50 g S)
- Solve the proportion for 'x':
- (1.50 g)(2.50 g) = (1.00 g)(x g)
- 3.75 g = x g
Therefore, the sample contains 3.75 g of molybdenum (Mo). Hence, option 'C' (3.75 g of Mo) is the correct answer.
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The element molybdenum (Mo) combines with sulphur (S) to form a compound commonly called molybdenum disulphide which used in specialized lithium batteries. A sample of this compound contains 1.50 g of Mo for each 1.00 g of S. If a different sample of the compound contains 2.50 g of S, how many grams of Mo does it contain?a)2.00 g of Mob)1.75 g of Moc)3.75 g of Mod)5.75 g of MoCorrect answer is option 'C'. Can you explain this answer?
Question Description
The element molybdenum (Mo) combines with sulphur (S) to form a compound commonly called molybdenum disulphide which used in specialized lithium batteries. A sample of this compound contains 1.50 g of Mo for each 1.00 g of S. If a different sample of the compound contains 2.50 g of S, how many grams of Mo does it contain?a)2.00 g of Mob)1.75 g of Moc)3.75 g of Mod)5.75 g of MoCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The element molybdenum (Mo) combines with sulphur (S) to form a compound commonly called molybdenum disulphide which used in specialized lithium batteries. A sample of this compound contains 1.50 g of Mo for each 1.00 g of S. If a different sample of the compound contains 2.50 g of S, how many grams of Mo does it contain?a)2.00 g of Mob)1.75 g of Moc)3.75 g of Mod)5.75 g of MoCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The element molybdenum (Mo) combines with sulphur (S) to form a compound commonly called molybdenum disulphide which used in specialized lithium batteries. A sample of this compound contains 1.50 g of Mo for each 1.00 g of S. If a different sample of the compound contains 2.50 g of S, how many grams of Mo does it contain?a)2.00 g of Mob)1.75 g of Moc)3.75 g of Mod)5.75 g of MoCorrect answer is option 'C'. Can you explain this answer?.
The element molybdenum (Mo) combines with sulphur (S) to form a compound commonly called molybdenum disulphide which used in specialized lithium batteries. A sample of this compound contains 1.50 g of Mo for each 1.00 g of S. If a different sample of the compound contains 2.50 g of S, how many grams of Mo does it contain?a)2.00 g of Mob)1.75 g of Moc)3.75 g of Mod)5.75 g of MoCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The element molybdenum (Mo) combines with sulphur (S) to form a compound commonly called molybdenum disulphide which used in specialized lithium batteries. A sample of this compound contains 1.50 g of Mo for each 1.00 g of S. If a different sample of the compound contains 2.50 g of S, how many grams of Mo does it contain?a)2.00 g of Mob)1.75 g of Moc)3.75 g of Mod)5.75 g of MoCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The element molybdenum (Mo) combines with sulphur (S) to form a compound commonly called molybdenum disulphide which used in specialized lithium batteries. A sample of this compound contains 1.50 g of Mo for each 1.00 g of S. If a different sample of the compound contains 2.50 g of S, how many grams of Mo does it contain?a)2.00 g of Mob)1.75 g of Moc)3.75 g of Mod)5.75 g of MoCorrect answer is option 'C'. Can you explain this answer?.
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