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Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.
(Specific heat of water = 4.2 J/g/°C
Specific heat of Ice = 2.1 J/g/°C
Heat of fusion of water at 0°C = 334 J/g)
Correct answer is '40'. Can you explain this answer?
Verified Answer
Ice at -20°C is added to 50 g of water at 40°C. When the tempe...
Let amount of ice is m gm.
According to principal of calorimeter heat taken by ice = heat given by water
∴ 20 × 2.1 ×  m + (m - 20) × 334
= 50 ×  4.2 ×  40
376 m = 8400 + 6680
m = 40
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Most Upvoted Answer
Ice at -20°C is added to 50 g of water at 40°C. When the tempe...
Ice at -20 degrees Celsius is very cold and solid. It will have a hard texture and will not easily break or melt. It can be used for keeping things cold for a longer period of time, such as in coolers or for preserving food.
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Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer?
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Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer?.
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