Question Description
Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
according to
the JEE exam syllabus. Information about Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer?.
Solutions for Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer?, a detailed solution for Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer? has been provided alongside types of Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Ice at -20°C is added to 50 g of water at 40°C. When the temperature of the mixture reaches 0°C, it is found that 20 g of ice is still unmelted. The amount of ice (in nearest integer) added to the water was _____g.(Specific heat of water = 4.2 J/g/°CSpecific heat of Ice = 2.1 J/g/°CHeat of fusion of water at 0°C = 334 J/g)Correct answer is '40'. Can you explain this answer? tests, examples and also practice JEE tests.