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The resistance of the meter bridge AB in given figure is 4Ω. With a cell of emf ε = 0.5V and rheostat resistance Rh = 2 ohm, the null point is obtained at some point J. When the cell is replaced by another one of emf ε = ε2 the same null point J is found for Rh = 6Ω. The emf εis k 
× 10
-1 V.
(Answer up to the nearest integer)
Correct answer is '3'. Can you explain this answer?
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The resistance of the meter bridge AB in given figure is 4Ω. Wit...
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The resistance of the meter bridge AB in given figure is 4Ω. With a cell of emfε = 0.5Vand rheostat resistance Rh= 2 ohm, the null point is obtained at some point J. When the cell is replaced by another one of emfε =ε2the same null point J is found for Rh= 6Ω.The emfε2isk× 10-1V.(Answer up to the nearest integer)Correct answer is '3'. Can you explain this answer?
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The resistance of the meter bridge AB in given figure is 4Ω. With a cell of emfε = 0.5Vand rheostat resistance Rh= 2 ohm, the null point is obtained at some point J. When the cell is replaced by another one of emfε =ε2the same null point J is found for Rh= 6Ω.The emfε2isk× 10-1V.(Answer up to the nearest integer)Correct answer is '3'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The resistance of the meter bridge AB in given figure is 4Ω. With a cell of emfε = 0.5Vand rheostat resistance Rh= 2 ohm, the null point is obtained at some point J. When the cell is replaced by another one of emfε =ε2the same null point J is found for Rh= 6Ω.The emfε2isk× 10-1V.(Answer up to the nearest integer)Correct answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The resistance of the meter bridge AB in given figure is 4Ω. With a cell of emfε = 0.5Vand rheostat resistance Rh= 2 ohm, the null point is obtained at some point J. When the cell is replaced by another one of emfε =ε2the same null point J is found for Rh= 6Ω.The emfε2isk× 10-1V.(Answer up to the nearest integer)Correct answer is '3'. Can you explain this answer?.
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