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In the base (OH) hydrolysis of a transition metal complex [ML6]z+, the slope between log (k/k0) and √I is found to be -2.1. The charge on the complex is:
  • a)
    +1
  • b)
    +2
  • c)
    +3
  • d)
    +4
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In the base (OH–) hydrolysis of a transition metal complex [ML6]...
Primary Kinetic Salt Effect:
  • The effect of electrolyte concentration on the rate constants of a number of reactions involving ions in aqueous solutions can be explained in terms of transition state theory and the Debye-Hückel theory.
  • The primary kinetic salt effect is the study of the effect of adding an inner electrolyte to an ionic reacting system.
  • It is the modification of the transition state theory for ionic reactions.
  • For the chemical reaction,
AzA + BzB → Products
If we look at the reaction above and reconsider it in terms of the formation of an activated complex,
AzA + BzB → X → Products 
Then, according to the transition theory, the equilibrium constant for the above reaction will be,

[As, Activity (a)= Concentration(c) × activity coefficient]
in which X is the activated complex that is formed in the transition state, γ’s are the activity coefficients.
  • From the above equation, using transition state theory the activity coefficient terms can be estimated from the DebyeHückel theory in dilute solutions. At 298 K 
  • This is known as the Brønsted equation and it predicts that the plot of log(k) versus the square root of ionic strength I should be a straight line.
  • For an aqueous solution, the slope is nearly equal to ZAZB, the product of the ionic charges. Three special cases could occur:
    • If ZA and ZB have the same sign, then ZAZB is positive, and the rate constant increases with ionic strength.
    • If ZA and ZB have different signs, ZAZB is negative and the rate constant decreases with ionic strength.
    • If one of the reactants is uncharged, ZAZB is zero and the rate constant is independent of the ionic strength.
the slope between log (k/k0) and √I  is found to be -2.1.
From above equation no 2
slope = 2AZaZb
The value of A is 0.509
−2.1=2∗0.509ZaZalso value of Zb is -1
−2.1=2∗0.509(−1)Za
Za =+2.06 
or nearly equal to +2.
Hence, If the charge of one ion is -1, the charge of other ion is close to +2
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In the base (OH–) hydrolysis of a transition metal complex [ML6]z+, the slope between log (k/k0) and √I is found to be -2.1. The charge on the complex is:a)+1b)+2c)+3d)+4Correct answer is option 'B'. Can you explain this answer?
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In the base (OH–) hydrolysis of a transition metal complex [ML6]z+, the slope between log (k/k0) and √I is found to be -2.1. The charge on the complex is:a)+1b)+2c)+3d)+4Correct answer is option 'B'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about In the base (OH–) hydrolysis of a transition metal complex [ML6]z+, the slope between log (k/k0) and √I is found to be -2.1. The charge on the complex is:a)+1b)+2c)+3d)+4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the base (OH–) hydrolysis of a transition metal complex [ML6]z+, the slope between log (k/k0) and √I is found to be -2.1. The charge on the complex is:a)+1b)+2c)+3d)+4Correct answer is option 'B'. Can you explain this answer?.
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