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The reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson’s catalyst provided 9.2g of alkene B. The mol % of the catalyst used and the yield of the reaction, approximately are
  • a)
    1.0 mol%; and 80%
  • b)
    1.0 mol %; and 90%
  • c)
    0.1 mol%; and 90%
  • d)
    0.2 mol %; and 80%
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson&rsqu...
This problem can be solved using the mole concept
  • 1 mol of A reacts with (Ph3P)RhCl to form 1 mol of B.
  • Now,
1 mol of A = 1 mol of B
11.6/232 mole of A = 9.2/204 mole of B
0.05 mole of A = 0.045 mole of B
  • Thus, the % yield of B is,
= (0.045/0.05) x 100%
= 90 %
  • The use of catalyst in term of percentage mole can be calculated as 11.6/232 mole is used with 9.2/204 mole of catalyst is ​0.05 mole of A = 0.005 mole of Catalyst
  • Thus, the mol % of the catalyst used
    = (0.005/0.05) x 100%
    = 1%
Hence, the mol % of the catalyst used and the yield of the reaction, approximately are 1.0 mol %; and 90%.
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The reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson’s catalyst provided 9.2g of alkene B. The mol % of the catalyst used and the yield of the reaction, approximately area)1.0 mol%; and 80%b)1.0 mol %; and 90%c)0.1 mol%; and 90%d)0.2 mol %; and 80%Correct answer is option 'B'. Can you explain this answer?
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The reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson’s catalyst provided 9.2g of alkene B. The mol % of the catalyst used and the yield of the reaction, approximately area)1.0 mol%; and 80%b)1.0 mol %; and 90%c)0.1 mol%; and 90%d)0.2 mol %; and 80%Correct answer is option 'B'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson’s catalyst provided 9.2g of alkene B. The mol % of the catalyst used and the yield of the reaction, approximately area)1.0 mol%; and 80%b)1.0 mol %; and 90%c)0.1 mol%; and 90%d)0.2 mol %; and 80%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction of 11.6 g of the aldehyde A with 462 mg of Wilkinson’s catalyst provided 9.2g of alkene B. The mol % of the catalyst used and the yield of the reaction, approximately area)1.0 mol%; and 80%b)1.0 mol %; and 90%c)0.1 mol%; and 90%d)0.2 mol %; and 80%Correct answer is option 'B'. Can you explain this answer?.
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